我正在为dio创建一个类 我与服务器的所有连接都发生在此类中 现在我想在其他类中调用onError和onSuccess 一个例子是在Java中通过接口完成的
谢谢
答案 0 :(得分:0)
我已经做到了 首先,创建一个通用的dio类,
class NetworkRepository {
Future<String> getRequest(String url) async {
var dio = Dio();
print(url.toString());
dio.interceptors.add(InterceptorsWrapper(
onRequest:(RequestOptions options) async {
print("REQUEST[${options?.method}] => PATH: ${options?.path}");
return options; //continue
},
onResponse:(Response response) async {
print("RESPONSE[${response?.statusCode}] => PATH: ${response?.request?.path}");
return response; // continue
},
onError: (DioError err) async {
print("ERROR[${err.toString()}] => PATH: ${err?.request?.path}");
return err;//continue
}
));
Response response = await dio.get(url);
print(response.toString());
return response.toString();
}
dynamic requestInterceptor(RequestOptions options) async {
return options;
}
}
,并且您想在任何班级中调用它时,
NetworkRepository().getRequest(projects).then((onValue) {
var dataConvertedToJSON = json.decode(onValue);
print(dataConvertedToJSON);
setState(() {
ProjectModel model = ProjectModel.fromJson(dataConvertedToJSON);
mList.add(model);
});
});
您也可以尝试Bloc pattern这样做。