Question

assassin_weapons = {'dagger':6,'blade':10,'hidden_blade':7,'sai':7,'tomahawk':11,'spear':9}

assassin_armour = {'chest_guard':21,'gauntlets':6,'boots':9,'hood':12,'cape':16}

def store():

    if char_class == 'Assassin':
        time.sleep(0.6)
        print(assassin_weapons)
        time.sleep(0.6)
        purchase = input("Which item(s) do you want to purchase?: ")
        for key in assassin_weapons:
            if key == purchase:
                Assassin.unequipped.update(**assassin_weapons[key])
                print(Assassin.unequipped)

Answer 1

此循环是不必要的，因为您只有一个键，而不必通过字典来循环获得它。

for key in assassin_weapons:
            if key == purchase:
                Assassin.unequipped.update(**assassin_weapons[key])
                print(Assassin.unequipped)

我认为您想要做的是，获取他购买的物品并将其带到Assassin.unequipped词典中？如果是，则获取该键和值并将其添加到新字典中。

if purchase in assassin_weapons:
   if purchase in Assassin.unequipped:
      Assassin.unequipped[purchase]+=assassin_weapons[purchase]
   else:
      Assassin.unequipped[purchase]=assassin_weapons[purchase]
   # type 1 instead of assassin_weapons[purchase] if you want only one item to purchase

有没有一种方法可以使用用户输入将键值从另一个字典添加到字典

1 个答案: