如何实现带寄存器的4位加法器的体系结构?希望您能更好地理解此图对我的要求
编辑1:
当复位信号为1时,寄存器r1获得0001,而寄存器r2获得0000
ListView {
id: view
width: 180; height: 200
focus: true
model: textModel
delegate: RowLayout{
id: layout
Label {
text: model.text
}
TextField {
focus: layout.ListView.isCurrentItem
text: model.text
}
}
// Component.onCompleted: view.currentIndex = 0
}