我正在尝试编写一个脚本来读取XML文件,将其插入表单中,然后使用php编辑和更新值。
该表单会加载当前数据,但不会更新它们。
有人可以告诉我小费吗? 谢谢毛里齐奥
文件XML
<?xml version="1.0" encoding="UTF-8"?>
<myxml>
<data name="en_title"><![CDATA[mytitle]]></data>
<data name="en_scene_title"><![CDATA[ES000021903]]></data>
</myxml>
文件编辑PHP
<?php
$form_fields = null;
$data = simplexml_load_file('messages_en.xml');
foreach($data->data as $field)
{
$form_fields .= '<div>';
$form_fields .= '<label>' .$field['name'] . ' </label>';
$form_fields .= '<input type="text" id="' .$field['name'] . '"placeholder="'.htmlentities($field).'" name="'.$field. '" />';
$form_fields .= '</div>';
}
?>
<!DOCTYPE html>
<html>
<head>
<style>
form { font-size: 16px; }
form div { margin: .3em; }
legend { font-weight: bold; font-size: 20px; }
label { display:inline-block; width: 140px; }
</style>
</head>
<body>
<form method="POST" action="process.php">
<legend> Enter Contact Information</legend>
<?php echo $form_fields; ?>
<input type="submit" name="submit" value="Upload" class="btn" />
</form>
</body>
</html>
代码文件process.php
<?php
$xml = file_get_contents('messages_en.xml');
$sxml = simplexml_load_string($xml);
if(isset($sxml->item[$_POST['name']])) {
$node->data = $_POST['name'];
}
file_put_contents('messages_en.xml', $sxml->asXML());
?>
答案 0 :(得分:0)
是否要基于const core = require('@actions/core');
function run() {
try {
// This is just a thin wrapper around bash, and runs a file called "script.sh"
//
// TODO: Change this to run your script instead
//
const script = require('path').resolve(__dirname, 'script.sh');
var child = require('child_process').execFile(script);
child.stdout.on('data', (data) => {
console.log(data.toString());
});
child.on('close', (code) => {
console.log(`child process exited with code ${code}`);
process.exit(code);
});
}
catch (error) {
core.setFailed(error.message);
}
}
run()
元素的name
属性更新XML?
如果是这样,则需要a)从HTML中传递名称和值,并b)搜索所需的名称。
<data>