Question

我想遍历此列表（https://express-press-release.net/Industries/Automotive-press-releases.php）上的每个URL，然后复制数据并返回到根目录以获取下一个URL。我可以从单个页面抓取，但不能通过多个链接抓取。

Answer 1

您可以使用href找到所有<a>标签，并将它们放入列表中。然后只需遍历该列表即可。您可能需要添加一些其他类型的过滤器，因为您可能只想要特定的链接，但这可以助您一臂之力：

import requests
from bs4 import BeautifulSoup

url = 'https://express-press-release.net/Industries/Automotive-press-releases.php'

response = requests.get(url)
soup = BeautifulSoup(response.text, 'html.parser')

links = soup.find_all('a', href=True)

root = 'https://express-press-release.net/'

link_list = [ root + a['href'] for a in links if '..' in a['href'] ]

for link in link_list:
    do some stuff...

Python多层网页抓取

1 个答案: