Question

在我的Rails应用程序中，我使用Braintree gem创建订阅。在没有意识到的情况下，我还创建了一个Subscription模型和控制器来管理我想在本地存储的订阅信息。在我的模型中，订阅可以属于用户。但是，你可以做的一些正常的东西是没有工作的 current_user.subscriptions.build（）

但出于某种原因，当有人帮助我时，他们可以使用

current_user.create_subscription

这个create_subscription方法定义在哪里？它是否以某种方式凌驾于Rails惯例之上？

我注意到Braintree gem中有一个subscription.rb文件。是否与Braintree和我的订阅模型定义的类存在冲突？我知道我可能只是重命名我的订阅模型，但我很好奇冲突是什么。

Answer 1

您的问题是订阅关系是has_one或belongs_to，而不是has_many。在这种情况下，用户将没有订阅方法，因为附加的订阅将是单数的。查看API文档，了解如何在AR中操纵这些类型的关系。

来自has_one：

的手册

The following methods for retrieval and query of a single associated object will be added:

association(force_reload = false)

Returns the associated object. nil is returned if none is found.

association=(associate)

Assigns the associate object, extracts the primary key, sets it as the foreign key, and saves the associate object.

build_association(attributes = {})

Returns a new object of the associated type that has been instantiated with attributes and linked to this object through a foreign key, but has not yet been saved. Note: This ONLY works if an association already exists. It will NOT work if the association is nil.

create_association(attributes = {})

Returns a new object of the associated type that has been instantiated with attributes, linked to this object through a foreign key, and that has already been saved (if it passed the validation).

Braintree确实有一个Subscription类，但它被命名为Braintree：Subscription，因此它不是问题。

Rails Braintree宝石订阅类冲突

1 个答案: