Question

我有很长的汽车广告标题列表，还有所有汽车品牌和型号的另一个列表，我正在搜索标题以在品牌/型号列表中找到匹配项。到目前为止，我已经知道了：

    for make in carmakes:
        if make in title:
            return make

但是它的效果不是很好，因为标题是人为制作的，并且有很多变化。例如，如果标题是“ Nissan D-Max”，而我的品牌/型号列表中有“ dmax”，则循环不会捕获到它，因为它不完全匹配。 “松散”或“动态”检查匹配的最佳方法是什么？

Answer 1

一旦遇到类似的挑战，下面是简化的解决方案：

import re

def re_compile(*args, flags: int =re.IGNORECASE, **kwargs):
    return re.compile(*args, flags=flags, *kwargs)

class Term(object):
    """"""
    def __init__(self, contain_patterns, *contain_args):
        self.matching_rules = []
        self.forbid_rules = []
        if isinstance(contain_patterns, str):
            self.may_contain(contain_patterns, *contain_args)
        else:
            for cp in contain_patterns:
                self.may_contain(cp, *contain_args)

    def __eq__(self, other):
        return isinstance(other, str) and self.is_alias(other)

    def is_alias(self, s: str):
        return (
            all(not f_rule(s) for f_rule in self.forbid_rules) and
            any(m_rule(s) for m_rule in self.matching_rules)
        )

    def matching_rule(self, f):
        self.matching_rules.append(f)
        return f

    def forbid_rule(self, f):
        self.forbid_rules.append(f)
        return f

    def must_rule(self, f):
        self.forbid_rules.append(lambda s: not f(s))
        return f

    def may_be(self, *re_fullmatch_args):
        self.matching_rules.append(re_compile(*re_fullmatch_args).fullmatch)

    def must_be(self, *re_fullmatch_args):
        fmatch = re_compile(*re_fullmatch_args).fullmatch
        self.forbid_rules.append(lambda s: not fmatch(s))

    def must_not_be(self, *re_fullmatch_args):
        self.forbid_rules.append(re_compile(*re_fullmatch_args).fullmatch)

    def may_contain(self, *re_search_args):
        self.matching_rules.append(re_compile(*re_search_args).search)

    def must_not_contain(self, *re_search_args):
        self.forbid_rules.append(re_compile(*re_search_args).search)

    def may_starts_with(self, *re_match_args):
        self.matching_rules.append(re_compile(*re_match_args).match)

    def must_not_starts_with(self, *re_match_args):
        self.forbid_rules.append(re_compile(*re_match_args).match)

在您的情况下，每个car_model都应表示为具有自正则表达式规则的Term实例（我对汽车品牌不太了解，我发明了一些名称）：

if __name__ == '__main__':
    dmax = Term((r'd[ -._\'"]?max', r'Nissan DM'))
    dmax.may_contain(r'nissan\s+last\s+(year)?\s*model')
    dmax.must_not_contain(r'Skoda')
    dmax.must_not_contain(r'Volkswagen')

    @dmax.matching_rule
    def dmax_check(s):
        return re.search(r'double\s+max', s, re.IGNORECASE) and re.search(r'nissan', s, re.IGNORECASE)

    tg = Term(r'Tiguan')
    octav = Term(r'Octavia')

    titles = (
        'Dmax model',
        'd_Max nissan',
        'Nissan Double Max Pro',
        'nissan last model',
        'Skoda octavia',
        'skoda d-max',
        'Nissan Qashqai',
        'VW Polo double max'
    )

您的示例：

for car_model in (dmax, tg, octav):
    print(car_model in titles)

结果：

True
False
True

详细信息：

print(' '*26, 'DMAX TIGUAN OCTAVIA')
for title in titles:
    print(title.ljust(26), (dmax == title), (tg == title), (octav == title))

结果：

                           DMAX TIGUAN OCTAVIA
Dmax model                 True False False
d_Max nissan               True False False
Nissan Double Max Pro      True False False
nissan last model          True False False
Skoda octavia              False False True
skoda d-max                False False False
Nissan Qashqai             False False False
VW Polo double max         False False False

如何“宽松地”检查字符串是否与列表中的另一个字符串匹配

1 个答案: