Question

使用python2.7，我想生成一个新列表，输入/输出如下。想要做一个简单的方法...

输入：

l1=['1','2'] 
l2=['a','b','c','d']
l3=['x','y','z']

#expect output:
['1ax','1bx','1cx','2dx','1ay','1by','1cy','2dy',.......]

Answer 1

使用以下代码：

l1=['1','2'] 
l2=['a','b','c','d']
l3=['x','y','z']

final_arr = list()
for i in l1:
    for j in l2:
        for k in l3:
            final_arr.append('{}{}{}'.format(i,j,k))

print(final_arr)
['1ax', '1ay', '1az', '1bx', '1by', '1bz', '1cx', '1cy', '1cz', '1dx', '1dy', '1dz', '2ax', '2ay', '2az', '2bx', '2by', 
'2bz', '2cx', '2cy', '2cz', '2dx', '2dy', '2dz']

Answer 2

您可以将乘数更改为更远，但这会使您的数字变为偶数：

from functools import reduce
import operator
l1=['1','2'] 
l2=['a','b','c','d']
l3=['x','y','z']

newlist=[] 
for item in zip(l1*6,l2*3,l3*4): 
   newlist.append(reduce(operator.add, item)) 

newlist 
#['1ax', '2by', '1cz', '2dx', '1ay', '2bz', '1cx', '2dy', '1az', '2bx', '1cy', '2dz']

如何以简单的方式实现此列表

2 个答案: