Question

在C＃和Java中，您可以输入任何类型的数据-int，string，float，long-，而不会排除其他类型。

所以我想知道在C ++中有什么方法可以做到这一点吗？

由于与C＃或Java不同，Object或Obj无法正常工作，坦率地说，我已经搜索了一段时间，但尚未得出结论。

我要使用的Function \ Method是从整数，字符串等中获取任何输入...或\和用户输入，然后将其打印回控制台。

代码是：

static void P(Object x) { cout << x;}

Answer 1

使用模板：

def my_det(X):
    '''
    Parameters
    ----------
    X : array_like

    Returns
    -------
    det : float
        Determinant of `a`.
    Plan
    ----
    Iterate through columns, create nested loop to iterate through all elements below
    the main diagonal, assign a scaler according to the value, iterate through all 
    elements in the row to change them according to the scaler. Finally, compute
    determinant.

    '''

    dimensionX, dimensionY = X.shape
    if dimensionX == dimensionY:
        matrixCopy = X.copy()
        for i in range(dimensionX):  # make only the diagonal non-zero
            for getZero in range(i + 1, dimensionX):  # make all elements below i-th zero(i.e. getZero elment = 0)
                if matrixCopy[i, i] == 0:  # cheating to create very small value
                    matrixCopy[i, i] == 1.0e-18
                rowScaler = matrixCopy[getZero, i] / matrixCopy[i, i]  # to change the rows accordingly
                print(rowScaler)
                for j in range(dimensionX):  # change every element in the row
                    matrixCopy[getZero, j] = float(matrixCopy[getZero, j]) - float(rowScaler * matrixCopy[i, j])
                    print(matrixCopy[getZero, j])
            print(matrixCopy)
        det = 1.0
        for detNum in range(dimensionX):  # TADAAAAAAM
            det *= matrixCopy[detNum, detNum]
        return det
    else:
        print('ValueError: wrong dimensions')


# matrix = np.random.randint(50, size=(3, 3))
matrix = np.array([[39, 24, 16], [24, 45, 47], [2, 7, 28]])
# matrix = np.array([[1, 1, 1], [1, 1, 1], [1, 1, 1]])
print(matrix)
print(my_det(matrix))

用法：

template <typename T>
void Print(const T& x)
{
    std::cout << x;
}

有没有办法在函数c ++中输入任何数据类型？

1 个答案: