Matplotlib获取子图(轴)大小吗?

时间:2019-11-22 10:24:07

标签: python matplotlib

只是徘徊-如何在Matplotlib中获得子图(轴?)的大小?

如果我在https://matplotlib.org/3.1.1/api/axes_api.html中使用Ctrl-F“ size”-在上下文中只有一个匹配项:“ ...具有不同的标记大小和/或...”,因此它并不能真正说明我如何找到轴的尺寸。

说,我的代码与Interactively resize figure and toggle plot visibility in Matplotlib?

中的相同
#!/usr/bin/env python3

import matplotlib
print("matplotlib.__version__ {}".format(matplotlib.__version__))
import matplotlib.pyplot as plt
import numpy as np

default_size_inch = (9, 6)
showThird = False

def onpress(event):
  global fig, ax1, ax2, ax3, showThird
  if event.key == 'x':
    showThird = not showThird
    if showThird:
      fig.set_size_inches(default_size_inch[0]+3, default_size_inch[1], forward=True)
      plt.subplots_adjust(right=0.85) # leave a bit of space on the right
      ax3.set_visible(True)
      ax3.set_axis_on()
    else:
      fig.set_size_inches(default_size_inch[0], default_size_inch[1], forward=True)
      plt.subplots_adjust(right=0.9) # default
      ax3.set_visible(False)
      ax3.set_axis_off()
    fig.canvas.draw()


def main():
  global fig, ax1, ax2, ax3
  xdata = np.arange(0, 101, 1) # 0 to 100, both included
  ydata1 = np.sin(0.01*xdata*np.pi/2)
  ydata2 = 10*np.sin(0.01*xdata*np.pi/4)

  fig = plt.figure(figsize=default_size_inch, dpi=120)
  ax1 = plt.subplot2grid((3,3), (0,0), colspan=2, rowspan=2)
  ax2 = plt.subplot2grid((3,3), (2,0), colspan=2, sharex=ax1)
  ax3 = plt.subplot2grid((3,3), (0,2), rowspan=3)

  ax3.set_visible(False)
  ax3.set_axis_off()

  ax1.plot(xdata, ydata1, color="Red")
  ax2.plot(xdata, ydata2, color="Khaki")

  fig.canvas.mpl_connect('key_press_event', lambda event: onpress(event))
  plt.show()


# ENTRY POINT
if __name__ == '__main__':
  main()

如何找到由ax1和ax2轴表示的子图的大小?

1 个答案:

答案 0 :(得分:0)

有关 bbox 如何工作的完整说明,请参阅 here。每个轴对象都适合一个边界框。您需要做的就是获取轴边界框的高度和宽度。 ax_h, ax_w = ax.bbox.height, ax.bbox.width

您可以使用 bbox.transformed 方法转换为图形坐标。例如: ax_h = ax.bbox.transformed(fig.gca().transAxes).height