Question

HTML

<form method="post" action="">
                <input type="text" name="f_name" placeholder="الاسم الأول" required/><br>
                <input type="text" name="l_name" placeholder="اللقب" required/><br>
                <input type="text" name="email" placeholder="البريد" required/><br>
                <input type="text" name="birth" placeholder="تاريخ الميلاد" required/><br>
                <input type="text" name="city" placeholder="المدينة" required/><br>
                <select name="location">
                    <option value="almnshia">almnshia</option>
                      <option value="aljadid">aljadid</option>
                      <option value="algurda">algurda</option>
                      <option value="algurda">altanwya</option>
                </select>
                <input type="text" name="user_name" placeholder="اسم المستخدم" required/><br>
                <input type="text" name="desc" placeholder="الوصفة" required/><br>
                <select name="disab">
                    <option value="yes">yes</option>
                      <option value="no">no</option>
                </select><br>
                <input type="password" name="pass" placeholder="كلمة السر" required/><br>
                <input type="submit" name="done" value="signup"/>
            </form>

PHP插入

<?php

$servername="localhost";
$username="root";
$password="";
$database="exam";
//create connection
$conn=new mysqli($servername , $username , $password , $database);

if($conn->connect_error){
    die("connection failed:".$conn->connect_error);
}
else {
    echo "connected successfully";
}


if(isset($_POST['done'])){
            $f_name=$_POST['f_name'];
            $l_name=$_POST['l_name'];
            $email=$_POST['email']; 
            $birth=$_POST['birth'];
            $city=$_POST['city'];
            $location=$_POST['location'];
            $user_name=$_POST['user_name'];
            $desc=$_POST['desc'];
            $disab=$_POST['disab'];
            $pass=$_POST['pass'];


 $sql = "INSERT INTO exam1 (f_name, l_name, email,  birth,  city, location,  user_name, desc, disab, pass)
VALUES ('$f_name', '$l_name', '$email', '$birth', '$city', '$location', '$user_name', '$desc', '$disab', '$pass')";



if ($conn->query($sql) === TRUE) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . $conn->error;
}
}
?>

我收到的消息

已成功连接错误：插入INTO考试1（f_name，l_name，电子邮件，出生，城市，位置，用户名，desc，disab，通过）VALUES（“约翰”， “ doe”，“ TT@GMAIL.COM”，“ 1993”，“ sabh”，“ almnshia”，“ ali”，“ ss”，“ yes”， '120130'）您的SQL语法有误；检查手册对应于您的MySQL服务器版本以使用正确的语法 'desc，disab，pass附近）VALUES（'john'，'doe'，'TT@GMAIL.COM'，第1行的'1993'，'sabh'，'almn'

我使用navicat lite 我确定数据库名称和表名称以及表中的字段名称

我无法将数据插入到navicat表中

0 个答案: