Question

我有一个PhidgetBridge，它连接到2号应变仪。我收到信号并使用此代码进行校准。但是，当我运行它时，它只显示一张打印，或者我想打印很多（使用此代码，我希望以50ms（即20 Hz）的数据间隔打印数据）。

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Answer 1

您只需要一个无限循环（while True）即可运行，直到引发KeyboardInterrupt异常为止。此外，为了每隔50毫秒运行一次打印新结果，您只需要在sleep(0.05)循环的末尾添加while：

from time import sleep
from Phidget22.Phidget import *
from Phidget22.Devices.VoltageRatioInput import *
import time
import datetime

TIME_OUT = 5000 #5s beofre it throws a timeout exception 
DATA_INTERVAL = 50 #1000ms sample frequency 

A0 = -6.128983223994E-06
B0 = -0.000059639277340

A1 = -6.101017778744E-06
B1 = -0.000286467338645

def onVoltageRatioChange0(self, voltageRatio):
    Masse = (voltageRatio - (B0) ) / (A0)
    self.masse = Masse

def onVoltageRatioChange1(self, voltageRatio):
    Masse = (voltageRatio - (B1) ) / (A1)
    self.masse = Masse

def results():
        voltageRatioInput0 = VoltageRatioInput()
        voltageRatioInput0.masse = 0
        voltageRatioInput0.setChannel(0)
        voltageRatioInput0.setOnVoltageRatioChangeHandler(onVoltageRatioChange0)
        voltageRatioInput0.openWaitForAttachment(TIME_OUT)
        voltageRatioInput0.setBridgeGain(BridgeGain.BRIDGE_GAIN_128)
        voltageRatioInput0.setDataInterval(DATA_INTERVAL)

        voltageRatioInput1 = VoltageRatioInput()
        voltageRatioInput1.masse = 0
        voltageRatioInput1.setChannel(1)
        voltageRatioInput1.setOnVoltageRatioChangeHandler(onVoltageRatioChange1)
        voltageRatioInput1.openWaitForAttachment(TIME_OUT)
        voltageRatioInput1.setBridgeGain(BridgeGain.BRIDGE_GAIN_128)
        voltageRatioInput1.setDataInterval(DATA_INTERVAL)

        print(str(voltageRatioInput0.masse) + " / " + str(voltageRatioInput1.masse))

        voltageRatioInput0.close()
        voltageRatioInput1.close()

if __name__ == '__main__':
    try:
        while True:
            results()

            # Finally sleep for 50ms
            sleep(0.05)

    except KeyboardInterrupt:
        print("Goodbye")
        pass

Answer 2

我已将您的代码改编为使用While循环：

from Phidget22.Phidget import *
from Phidget22.Devices.VoltageRatioInput import *
import time
import datetime

TIME_OUT = 5000  # 5s beofre it throws a timeout exception
DATA_INTERVAL = 50  # 1000ms sample frequency

A0 = -6.128983223994E-06
B0 = -0.000059639277340

A1 = -6.101017778744E-06
B1 = -0.000286467338645


def onVoltageRatioChange0(self, voltageRatio):
    Masse = (voltageRatio - (B0)) / (A0)
    self.masse = Masse


def onVoltageRatioChange1(self, voltageRatio):
    Masse = (voltageRatio - (B1)) / (A1)
    self.masse = Masse


def main():
    while True:

        voltageRatioInput0 = VoltageRatioInput()
        voltageRatioInput0.masse = 0
        voltageRatioInput0.setChannel(0)
        voltageRatioInput0.setOnVoltageRatioChangeHandler(
            onVoltageRatioChange0)
        voltageRatioInput0.openWaitForAttachment(TIME_OUT)
        voltageRatioInput0.setBridgeGain(BridgeGain.BRIDGE_GAIN_128)
        voltageRatioInput0.setDataInterval(DATA_INTERVAL)

        voltageRatioInput1 = VoltageRatioInput()
        voltageRatioInput1.masse = 0
        voltageRatioInput1.setChannel(1)
        voltageRatioInput1.setOnVoltageRatioChangeHandler(
            onVoltageRatioChange1)
        voltageRatioInput1.openWaitForAttachment(TIME_OUT)
        voltageRatioInput1.setBridgeGain(BridgeGain.BRIDGE_GAIN_128)
        voltageRatioInput1.setDataInterval(DATA_INTERVAL)

        print(
            str(voltageRatioInput0.masse) + " / " +
            str(voltageRatioInput1.masse))

        try:
            input("Press Enter to Stop\n")
        except (Exception, KeyboardInterrupt):
            pass

        voltageRatioInput0.close()
        voltageRatioInput1.close()
        sleep(0.05)

main()

但是您的代码将在每次迭代时停止并等待输入，因此更好的实现是：

import os
import sys
import select
from Phidget22.Phidget import *
from Phidget22.Devices.VoltageRatioInput import *
import time
import datetime

TIME_OUT = 5000  # 5s beofre it throws a timeout exception
DATA_INTERVAL = 50  # 1000ms sample frequency

A0 = -6.128983223994E-06
B0 = -0.000059639277340

A1 = -6.101017778744E-06
B1 = -0.000286467338645


def onVoltageRatioChange0(self, voltageRatio):
    Masse = (voltageRatio - (B0)) / (A0)
    self.masse = Masse


def onVoltageRatioChange1(self, voltageRatio):
    Masse = (voltageRatio - (B1)) / (A1)
    self.masse = Masse


def main():
    while True:

        voltageRatioInput0 = VoltageRatioInput()
        voltageRatioInput0.masse = 0
        voltageRatioInput0.setChannel(0)
        voltageRatioInput0.setOnVoltageRatioChangeHandler(
            onVoltageRatioChange0)
        voltageRatioInput0.openWaitForAttachment(TIME_OUT)
        voltageRatioInput0.setBridgeGain(BridgeGain.BRIDGE_GAIN_128)
        voltageRatioInput0.setDataInterval(DATA_INTERVAL)

        voltageRatioInput1 = VoltageRatioInput()
        voltageRatioInput1.masse = 0
        voltageRatioInput1.setChannel(1)
        voltageRatioInput1.setOnVoltageRatioChangeHandler(
            onVoltageRatioChange1)
        voltageRatioInput1.openWaitForAttachment(TIME_OUT)
        voltageRatioInput1.setBridgeGain(BridgeGain.BRIDGE_GAIN_128)
        voltageRatioInput1.setDataInterval(DATA_INTERVAL)

        print(
            str(voltageRatioInput0.masse) + " / " +
            str(voltageRatioInput1.masse))

        voltageRatioInput0.close()
        voltageRatioInput1.close()

        os.system('cls' if os.name == 'nt' else 'clear')
        print("I'm doing stuff. Press Enter to stop me!")

        if sys.stdin in select.select([sys.stdin], [], [], 0)[0]:
            break

        time.sleep(0.05)  # wait 50ms

main()

这不会阻塞，并且会破坏Enter的循环。

Answer 3

您可能想要执行以下操作：

import time

while True:
    try:

        print('my code output') #substitute this line with your code

        time.sleep(0.05) #50 ms interval

    except KeyboardInterrupt:
        answer = input("Quit? Y/N")
        if answer.upper() == 'Y':
            break

print('Program terminated by the user')

使用键盘停止运行时运行Python代码

3 个答案: