Question

我已经提取了Kotlin输出的Teamcity版本。我想创建一个基类，该基类定义了许多常用的步骤/设置，但允许单独的构建来扩展这些属性。

例如

open class BuildBase(init: BuildBase.() -> Unit) : BuildType({
    steps {
        powerShell {
            name = "Write First Message"
            id = "RUNNER_FirstMessage"
            scriptMode = script {
                content = """
                    Write-Host "First Message"
                """.trimIndent()
            }
        }
    }
})

object Mybuild : BuildBase({
    steps { // This would add a new step to the list, without wiping out the original step
        powerShell {
            name = "Write Last Message"
            id = "RUNNER_LastMessage"
            scriptMode = script {
                content = """
                    Write-Host "Last Message"
                """.trimIndent()
            }
        }
    }
})

在此示例中，我想从基类继承步骤，但是添加与特定构建相关的其他步骤。另外，我想继承基本的disableSettings（如果有）并禁用其他步骤。

这甚至可能吗？如果是这样，我将如何构建类以启用它？

Answer 1

您可能已经找到了解决方案，但这是我将解决您的问题的方法。

就像GUI中一样，TeamCity支持构建模板。在您的情况下，您将具有如下模板：

object MyBuildTemplate: Template({
  id("MyBuildTemplate")
  name = "My build template"

  steps {
    powerShell {
        name = "Write First Message"
        id = "RUNNER_FirstMessage"
        scriptMode = script {
            content = """
                Write-Host "First Message"
            """.trimIndent()
        }
    }
  }
})

然后，您可以定义扩展此模板的构建配置：

object MyBuildConfig: BuildType({
  id("MyBuildConfig")
  name = "My build config"

  steps { // This would add a new step to the list, without wiping out the original step
    powerShell {
        name = "Write Last Message"
        id = "RUNNER_LastMessage"
        scriptMode = script {
            content = """
                Write-Host "Last Message"
            """.trimIndent()
        }
    }

    // afaik TeamCity would append the build config's steps to the template's steps but there is way to explicitly define the order of the steps:
    stepsOrder = arrayListOf("RUNNER_FirstMessage", "RUNNER_LastMessage")
  }
})

这样，您还应该能够从模板继承disableSettings。

Teamcity Kotlin构建基类属性扩展

1 个答案: