Question

我正在尝试在一个选择语句中使用多个汇总，并且停留在一个值基于另一个汇总的情况下（总收入是将CY乘以COUNT(TrackID)得出的）。

不允许我进行CTE，并且尝试使用子查询失败。三行注释掉的行是我失败的尝试（不是失败的子查询尝试，我已经删除了那些）。

Unit Price

我也尝试过这种方法，但是结果被忽略了

SELECT C.Country
    ,Ar.Name AS 'Artist Name'
    ,COUNT(T.TrackId) AS 'Track Count'
    ,COUNT(DISTINCT T.Name) AS 'Unique Track Count'
    ,COUNT(T.TrackID) - COUNT(DISTINCT T.Name) AS 'Count Difference'
    --,POWER(IL.UnitPrice,COUNT(T.TrackId)) AS 'Test'
    --,SUM(IL.UnitPrice * COUNT(T.TrackID)) AS 'Total Revenue'
    --,IL.UnitPrice * COUNT(T.TrackID) AS 'Total Revenue'
    ,CASE MediaTypeId
        WHEN 3
        THEN 'Video'
        ELSE 'Audio'
        END AS MediaType
FROM Artist Ar
JOIN Album Al
    ON Al.ArtistId = Ar.ArtistId
JOIN Track T 
    ON T.AlbumId = Al.AlbumId
JOIN InvoiceLine Il
    ON Il.TrackId = T.TrackId
JOIN Invoice I
    ON I.InvoiceId = Il.InvoiceId
JOIN Customer C
    ON C.CustomerId = I.CustomerId
GROUP BY Ar.Name
    ,C.Country
    ,CASE MediaTypeId
        WHEN 3
        THEN 'Video'
        ELSE 'Audio'
        END
ORDER BY C.Country ASC, COUNT(T.TrackID) DESC, Ar.Name ASC

Answer 1

您不能在同一查询中的计算中使用聚合，也不能在聚合中使用聚合，您需要将查询包装为内部查询，并在外部查询中使用聚合进行计算-

Select [columnsNames], [aggregates]
From
(
Your Inner Query
)a
Group By [columnsNames]
Order By [columnsNames]

汇总内的汇总

1 个答案: