我尝试使用在线Jsonify It工具,该工具可以从我的数据创建嵌套的JSON数据,但似乎无法正常工作。我也尝试过使用其他文章中的Python代码,但它们似乎也不起作用。如果您知道一种比使用Python更简单的方法,那会很好。
这是我的.CSV数据:
ID,Name,Date,Subject,Start,Finish
0,Ladybridge High School,01/11/2019,Maths,05:28,0
0,Ladybridge High School,02/11/2019,Maths,05:30,06:45
0,Ladybridge High School,01/11/2019,Economics,11:58,12:40
0,Ladybridge High School,02/11/2019,Economics,11:58,12:40
1,Loreto Sixth Form,01/11/2019,Maths,05:28,06:45
1,Loreto Sixth Form,02/11/2019,Maths,05:30,06:45
1,Loreto Sixth Form,01/11/2019,Economics,11:58,12:40
1,Loreto Sixth Form,02/11/2019,Economics,11:58,12:40
这是我想要的嵌套JSON结构:
{
"Timetable" : [ {
"Date" : {
"01-11-2019" : {
"Maths" : {
"Start" : "05:28",
"Finish" : "06:45"
},
"Economics" : {
"Start" : "11:58",
"Finish" : "12:40"
}
},
"02-11-2019" : {
"Maths" : {
"Start" : "05:30",
"Finish" : "06:45"
},
"Economics" : {
"Start" : "11:58",
"Finish" : "12:40"
}
}
},
"Name" : "Ladybridge High School"
}, {
"Date" : {
"01-11-2019" : {
"Maths" : {
"Start" : "05:28",
"Finish" : "06:45"
},
"Economics" : {
"Start" : "11:58",
"Finish" : "12:40"
}
},
"02-11-2019" : {
"Maths" : {
"Start" : "05:30",
"Finish" : "06:45"
},
"Economics" : {
"Start" : "11:58",
"Finish" : "12:40"
}
}
},
"Name" : "Loreto Sixth From"
} ]
}
答案 0 :(得分:2)
像这样吗?
[编辑]
我对其进行了重构,以处理时间表中每个条目的任意顶级键。我还让它首先创建了一个dict,然后将其转换为列表,以便在输入非常大的情况下可以在O(N)时间运行。
import csv
timetable = {}
with open('data.csv') as f:
csv_data = [{k: v for k, v in row.items()} for row in csv.DictReader(f, skipinitialspace=True)]
for row in csv_data:
if not timetable.get(row["ID"]):
timetable[row["ID"]] = {"ID": row["ID"], "Date": {}}
for k in row.keys():
# Date has to be handled as a special case
if k == "Date":
timetable[row["ID"]]["Date"][row["Date"]] = {}
timetable[row["ID"]]["Date"][row["Date"]][row["Subject"]] = {
"Start": row["Start"],
"Finish": row["Finish"]
}
# Ignore these keys because they are only for 'Date'
elif k == "Start" or k == "Finish" or k == "Subject":
continue
# Use everything else
else:
timetable[row["ID"]][k] = row[k]
timetable = {"Timetable": [v for k, v in timetable.items()]}
答案 1 :(得分:0)
上述答案的改进,用于将ID嵌套在名称和日期之前
import csv
timetable = {"Timetable": []}
print(timetable)
with open("C:/Users/kspv914/Downloads/data.csv") as f:
csv_data = [{k: v for k, v in row.items()} for row in csv.DictReader(f, skipinitialspace=True)]
name_array = []
for name in [row["Name"] for row in csv_data]:
name_array.append(name)
name_set = set(name_array)
for name in name_set:
timetable["Timetable"].append({"Name": name, "Date": {}})
for row in csv_data:
for entry in timetable["Timetable"]:
if entry["Name"] == row["Name"]:
entry["Date"][row["Date"]] = {}
entry["Date"][row["Date"]][row["Subject"]] = {
"Start": row["Start"],
"Finish": row["Finish"]
}
print(timetable)