我正在使用Airtable模板和Gridsome在产品目录模板中查询家具。在AirTable中,家具数据表具有“ designers”属性,该属性的值是创建家具的设计师的id。我的想法是使用该ID值创建另一个查询,并获取特定设计师的所有数据。设计师有自己的桌子,所以我的问题是。如何创建一个关系查询,以获取ID和“设计者”数据的路径?
我的gridsome.config.js
module.exports = {
siteName: 'Furniture Store',
plugins: [
{
use: '@gridsome/source-airtable',
options: {
apiKey: 'keyhMlUJl9q3uzk0b', // required
baseId: 'appkEp5El5UHrgnks', // required
tableName: 'Furniture', // required
typeName: 'Product', // required
}
},
{
use: '@gridsome/source-airtable',
options: {
apiKey: 'keyhMlUJl9q3uzk0b', // required
baseId: 'appkEp5El5UHrgnks', // required
tableName: 'Designers', // required
typeName: 'Designers', // required
}
},
],
templates: {
Designers: '/designer/:id' // optional
}
}
Index.vue
<template>
<Layout>
<h1>Furniture store</h1>
<ProductCard
v-for="product in $page.allProduct.edges"
:key="product.node.id"
:product="product"
/>
</Layout>
</template>
<page-query>
query {
allProduct {
edges {
node {
id
name
designer
description
type
inStock
images {
thumbnails {
large {
url
width
height
}
}
}
}
}
}
}
</page-query>
<script>
import ProductCard from '~/components/ProductCard';
export default {
components: {
ProductCard
}
}
</script>
components / ProductCard.vue
<template>
<v-app>
<v-card
class="mx-auto my-12"
max-width="374"
>
<v-img
height="250"
:src="product.node.images[0].thumbnails.large.url"
></v-img>
<v-card-title>{{ product.node.name }}</v-card-title>
<v-card-text>
<v-row
align="center"
class="mx-0"
>
<v-rating
:value="4.5"
color="amber"
dense
half-increments
readonly
size="14"
></v-rating>
<div class="grey--text ml-4">4.5 (413)</div>
</v-row>
<div class="my-4 subtitle-1 black--text">
{{ product.node.description }}
</div>
<g-link to="/">Link to Designer</g-link>
</v-card-text>
<v-divider class="mx-4"></v-divider>
<v-card-title>Tonight's availability</v-card-title>
</v-card>
</v-app>
</template>
<script>
export default {
name: 'ProductCard',
props: {
product: {
type: Object,
required: true,
},
},
}
</script>
templates / Designer.vue
<template>
<h1>{{ $page.designers.name }}</h1>
</template>
<page-query>
query Designer($id: ID!) {
designers(id: $id) {
name
id
bio
}
}
</page-query>
非常感谢任何帮助!