我必须从日期发送DDMMYYY日期以与API通信。
NSDateComponents * dateComponents; NSCalendar *格里高利; NSDate * date;
gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
dateComponents = [[NSDateComponents alloc] init];
self.date = [gregorian dateByAddingComponents:dateComponents toDate:[NSDate date] options:0];
我必须使用[dateComponents day]等吗?是否有一些方法可以帮助我像PHP一样执行该任务?
答案 0 :(得分:14)
试试这个
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"ddMMyyyy"];
NSString *textDate = [NSString stringWithFormat:@"%@",[dateFormatter stringFromDate:[NSDate date]]];
NSLog(@"Date %@",textDate);
[dateFormatter release];
答案 1 :(得分:1)
只需:
NSDateFormatter *outputFormatter = [[NSDateFormatter alloc] init];
[outputFormatter setDateFormat:@"ddMMyyyy"];
NSString *textDate = [NSString stringWithFormat:@"%@",[outputFormatter stringFromDate:[NSDate date]]];
[outputFormatter release];
答案 2 :(得分:1)
试试这段代码:
NSDateFormatter* dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[dateFormatter setLocale:[[[NSLocale alloc] initWithLocaleIdentifier:@"en_US_POSIX"] autorelease]];
[dateFormatter setDateFormat:@"ddMMyyyy"];
NSDate *current = [NSDate date];
NSString *currentstring = [dateFormatter stringFromDate:current]
答案 3 :(得分:1)
答案 4 :(得分:1)
NSDate *date=[NSDate date];
NSDateFormatter *formatter=[[NSDateFormatter alloc]init];
[formatter setDateFormat:@"ddMMyyyy"];
NSString *dateOfGame =[formatter stringFromDate:date];
[formatter release];
答案 5 :(得分:0)
试试这个:
NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[dateFormatter setDateFormat:@"ddMMyyyy"];
NSLog(@"%@", [dateFormatter stringFromDate:[NSDate date]]);
答案 6 :(得分:0)
同意 Ruben Esposito
只需更改您的代码即可。
NSDateFormatter *dtFormatter = [[NSDateFormatter alloc]init];
[dtFormatter setDateFormat:@"ddMMyyyy"];
NSString *strDate = [NSString stringWithFormat:@"%@",[dtFormatter stringFromDate:[NSDate date]]];
[dtFormatter release];
NSLog(@"%@",strDate);