Question

我需要遍历数据帧，并检查特定列的奇数行是否等于给定变量（偶数行相同）。

这是我的代码：

mydf = pd.read_excel(test.xlsx, header=0, index= False)
mydf = mydf.sort_values(by='Time') 
if ((mydf['Door Name'].iloc[::2]=='RDC_OUT-1') & (mydf['Door Name'].iloc[1::2]=='RDC_IN-1')):
    for i in range (l):
        mydf['diff'] = mydf['Times'].iloc[1::2].to_numpy() - mydf['Times'].iloc[::2]
        Total = mydf['diff'].sum()
        print('Total: ',Total)

但是当我运行它时，出现此错误：

if ((mydf['Door Name'].iloc[::2]=='RDC_OUT-1') & (mydf['Door Name'].iloc[1::2]=='RDC_IN-1')):

  File "C:\Users\khoul\AppData\Local\Continuum\anaconda3\lib\site-packages\pandas\core\generic.py", line 1478, in __nonzero__
    .format(self.__class__.__name__))

ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

这是我的数据框：

 Door name    Time                   Last Name   First Name
 RDC_IN-1     05/08/2019  15:23:00   aa          bb
 RDC_OUT-1    05/08/2019  12:39:00   aa          bb           
 RDC_IN-1     05/08/2019  12:13:00   aa          bb
 RDC_OUT-1    05/08/2019  09:10:00   aa          bb

我不知道为什么它不接受！

Answer 1

我的想法是，首先用Time用RDC_OUT-1选择所有已排序的行，然后选择下一个RDC_IN-1的值，然后再过滤掉另一行：

mydf = df.sort_values(by='Time') 

m1 = mydf['Door name'] == 'RDC_OUT-1'
m2 = mydf['Door name'] == 'RDC_IN-1'

m11 = m1 & m2.shift(-1)
m22 = m1.shift() & m2

df = mydf[m11 | m22]
print (mydf)
   Door name                Time Last Name First Name
3  RDC_OUT-1 2019-05-08 09:10:00        aa         bb
2   RDC_IN-1 2019-05-08 12:13:00        aa         bb
1  RDC_OUT-1 2019-05-08 12:39:00        aa         bb
0   RDC_IN-1 2019-05-08 15:23:00        aa         bb

因此，因为从注释中获得相同数量的IN和OUT行解决方案应该很好：

Total = (df.loc[df['Door name']=='RDC_IN-1','Time'] - 
         df.loc[df['Door name']=='RDC_OUT-1','Time'].to_numpy()).sum()
print('Total: ',Total)
Total:  0 days 05:47:00

检测奇数行和偶数行Python

1 个答案: