Question

如何使用C＃程序找到具有最高值的行和列？该程序要求用户输入程序中有多少行和多少列，然后要求输入数字。假设我在矩阵中放入4列和3行，然后输入以下数字：

89 11 22 44
29 51 80 20
33 10 45 10

在这种情况下，我需要的输出将是“第一个最大值位于行1和列1”。我如何使程序查找最大值所在的位置，直到该程序打印出最大值所在的行和列。当我尝试调用该方法以获取返回值时，它不会打印出来。这是我尝试的代码：

using System;

namespace locateLargest
{
    class Program
    {
        static void Main(string[] args)
        {
            int[,] arrayPart1 = new int[3, 4];

            for (int row = 0; row < arrayPart1.GetLength(0); row++)
            {
                for (int column = 0; column < arrayPart1.GetLength(1); column++)
                {
                    arrayPart1[row, column] = Convert.ToInt32(Console.ReadLine());
                }

            }





            for (int row = 0; row < arrayPart1.GetLength(0); row++)
            {
                for (int column = 0; column < arrayPart1.GetLength(1); column++)
                {
                    Console.Write("Value at [" + row + ", " + column + "]: " + arrayPart1[row, column] + "\t");
                }
                Console.WriteLine();
                 Console.WriteLine("The highest value in the array is at "+largest) 
            }

        }


            public static int[] LocateLargest(int[,] someArray)
                {

        {
            int largest = someArray[0, 0];
            int row, column;
            int maxRow = 0;
            int maxCol = 0;
            for (row = 0; row < someArray.GetLength(0); row++)
            {
                for (column = 0; column < someArray.GetLength(1); column++)
                {
                    if (someArray[row, column] > largest)
                    {
                        maxRow = row;
                        maxCol = column;
                        largest = someArray[row, column];
                    }
                }

            }
            return largest;

                }

            }
        }
    }

Answer 1

我认为这是初学者最简单的方法。

static void Main(string[] args)
{
    int[,] arrayPart1 = new int[3, 4];
    for (int row = 0; row < arrayPart1.GetLength(0); row++)
    {
        for (int column = 0; column < arrayPart1.GetLength(1); column++)
        {
            arrayPart1[row, column] = Convert.ToInt32(Console.ReadLine());
        }
    }

    for (int row = 0; row < arrayPart1.GetLength(0); row++)
     {
          for (int column = 0; column < arrayPart1.GetLength(1); column++)
          {
                Console.Write("Value at [" + row + ", " + column + "]: " + arrayPart1[row, column] + "\t");
          }
          Console.WriteLine();
          Console.WriteLine("The highest value in the array is at "+ LocateLargest (arrayPart1)).ToString ()) 
     }
}

int LocateLargest(int[,] someArray)
{
    int largest = someArray[0, 0];
    int row, column;
    int maxRow = 0;
    int maxCol = 0;
    for (row = 0; row < someArray.GetLength(0); row++)
    {
        for (column = 0; column < someArray.GetLength(1); column++)
         {
            if (someArray[row, column] > largest)
            {
                maxRow = row;
                maxCol = column;
                largest = someArray[row, column];
         }
     }
     Console.WriteLine("The largest value is at row " + maxRow.ToString() +  "and column " + maxCol.ToString());
    return largest; 
}

Answer 2

这对我有用：

var input = new []
{
    "89 11 22 44",
    "29 51 80 20",
    "33 10 45 10",
};

var result =
    input
        .Select((line, row) => new
        {
            row,
            columns =
                line
                    .Split(' ')
                    .Select((number, column) => new
                    {
                        column,
                        value = int.Parse(number)
                    }) 
        })
        .SelectMany(x => x.columns, (x, y) => new { x.row, y.column, y. value })
        .OrderByDescending(x => x.value)
        .First();

Console.WriteLine($"The largest value is {result.value} at row {result.row + 1} and column {result.column + 1}");

它给出：

第一行和第一列的最大值为89

如何找到具有最高价值的行和列？

2 个答案: