Question

我有一个包含四列的表

--------------------------------------
| ID | DESCRIPTION | PAY | TIMESTAMP |
--------------------------------------
| 1  | ABA123      | 100 | 02-10-2019|
--------------------------------------
| 2  | ABA123      | 200 | 02-06-2019|
--------------------------------------
| 3  | ABA123      | 300 | 01-11-2019|

根据我的要求，我需要获取1天的工资，5天的工资和1个月的工资，并假设今天是2019年3月11日。我可以运行三个查询以按以下方式获取数据。

select * from salary where timestamp <= sysdate -1 ; // this will return row with one day old salary
select * from salary where timestamp 
<= sysdate -1 and timestamp >= sysdate -4  // this one return all records between 1 to 4 days old and I can have similar query for one month old data

有什么方法可以运行一个查询，该查询将以以下格式显示结果

| DESCRIPTION | 1DAYPAY | 4DAYPAY | 1MONTHPAY |
----------------------------------------------------
| ABA123      | 100     | 200     | 300       |

Answer 1

您可以使用条件聚合。我不确定您想要的三个时期的确切逻辑是什么：

select description,
       max(case when timestamp >= sysdate - 1 then salary end),
       max(case when timestamp >= sysdate - 4 and timestamp < sysdate - 1 then salary end),      
       max(case when ? then salary end)  -- whatever the logic is for one month  
from salary
group by description;

您可能还需要sum()而不是max()。

Answer 2

使用sum()函数，然后add_months处理您的1 month旧数据。

select description
    , sum(case when timestamp between sysdate and sysdate - 1 then Pay else 0 end)
    , sum(case when timestamp between sysdate and sysdate - 4 then Pay else 0 end)
    , sum(case when timestamp between sysdate and add_months(sysdate,-1) then Pay else 0 end)
from salary
group by description

如何从同一表的同一列中获取不同的值-Oracle

2 个答案: