Question

我正在尝试对python列表的后半部分进行排序。在某些情况下，它起作用，在某些情况下，它不起作用。这种情况似乎无法通过程序执行： 6要素 [3,2,1,6,12,11]

这是我的代码：

#Initalizes the lists and prompts the user for the number of elements in the list
nums = []
original = []
sorter = []
elements = int(input("Please enter number of elements in list: "))

#Prompts the user to enter an element populating the nums list
for x in range(elements):
    nums.append(input("Enter element: "))

#Copies the nums list to original and sorter to modify the list for sorting
original = nums.copy()
sorter = nums.copy()

#Removes the first half of sorter and the second half of nums
for x in range(int(elements/2)):
    nums.pop()
    sorter.pop(0)

#Sorts the sorter list
sorter.sort()

#Prints the original list as well as the concatonated nums and sorter list
print("You entered: " + str(original))
print("Sorted: " + str(nums + sorter))

Answer 1

您正在输入字符串：

#Prompts the user to enter an element populating the nums list
for x in range(elements):
    nums.append(input("Enter element: "))

您想要整数：

#Prompts the user to enter an element populating the nums list
for x in range(elements):
    nums.append(int(input("Enter element: ")))

然后您的代码即可正常工作。

尽管您可能要考虑使用剪接和listcomp以获得更简单的方法：

elements = int(input("Please enter number of elements in list: "))
nums = [int(input("Enter element: ")) for _ in range(elements)]

sorted_nums = nums[:elements // 2] + sorted(nums[elements // 2:])

print("You entered:", nums)
print("Sorted:", sorted_nums)

Answer 2

我认为通过索引而不是循环，您可能会更轻松：

x = [3,2,1,6,12,11]
middle = int(len(x)/2)
sorted(x[middle:])

输出：[6, 11, 12]

排序列表的后半部分在某些情况下不起作用

2 个答案: