Question

环境

表agent_poll记录呼叫中心代理进行的呼叫总数，每1秒轮询一次电话系统以请求更新的总数。这样每天每个座席可以提供许多记录。

如下所述。

DESCRIBE agent_poll
Field        |Type        |Null|Key|Default             |Extra         |
-------------|------------|----|---|--------------------|--------------|
agent_poll_id|int(11)     |NO  |PRI|                    |auto_increment|
poll_time    |timestamp(6)|NO  |   |CURRENT_TIMESTAMP(6)|              |
agent_id     |int(11)     |NO  |MUL|                    |              |
agent_status |int(11)     |NO  |MUL|                    |              |
total_calls  |int(11)     |NO  |   |                    |              |

这是前十行-垃圾演示数据，因此不如生产中的常规数据

select * FROM agent_poll
agent_poll_id|poll_time                    |agent_id|agent_status|total_calls|
-------------|-----------------------------|--------|------------|-----------|
            1|          2019-11-12 12:02:01|       1|           1|         12|
            2|          2019-11-12 12:30:01|       4|           1|         12|
            3|          2019-11-12 12:34:18|       6|           4|         22|
            4|          2019-11-12 12:44:07|       1|           4|         22|
            5|          2019-11-14 12:15:44|       3|           3|          4|
            6|          2019-11-14 12:16:07|       1|           3|         23|
            7|          2019-11-14 12:21:42|       2|           3|          4|
            8|          2019-11-14 12:21:58|       5|           3|          4|
            9|          2019-11-14 12:22:47|       1|           1|         25|
           10|          2019-11-14 12:30:57|       2|           1|          4|

此外，这是座席状态表。

select * from agent_status
agent_status_id|agent_status_description|
---------------|------------------------|
              1|Available               |
              2|Break                   |
              3|Admin                   |
              4|On a Call               |
              5|Sick                    |
              6|Holiday                 |
              7|Away                    |

问题

您如何编写此查询？

如果agent_poll.agent_status为5、6或7，则返回agent_status，否则
返回每个座席在每个工作日最多可进行的total_calls呼叫

限制

应该是动态的，以允许将来扩展表-更多的业务代表，业务代表状态代码等
应该始终查询最近的日期

输出应如下所示。

Agent|Mon|Tue|Wed|Thu|Fri|
-----|---|---|---|---|---|
    1|   |   |   |   |   |
    2|   |   |   |   |   |
    3|   |   |   |   |   |
    4|   |   |   |   |   |
    5|   |   |   |   |   |
    6|   |   |   |   |   |
    7|   |   |   |   |   |
    8|   |   |   |   |   |
    9|   |   |   |   |   |
   10|   |   |   |   |   |
   11|   |   |   |   |   |
   12|   |   |   |   |   |
   13|   |   |   |   |   |

我尝试过的事情

我知道给定pivot正确的permissions是可能的。由于我将输出到仅具有只读权限的Grafana，因此我无法CREATE，UPDATE或DROP。

一个方法是使用虚拟表。这是TSQL开发人员向我建议的。

;WITH beepboop AS (
SELECT  B.agent_id,
        CASE WHEN WEEKDAY(B.poll_time) = 'Monday' THEN MAX(B.total_calls) ELSE NULL END AS 'Monday Calls', #one bin for the data to go into
        CASE WHEN WEEKDAY(B.poll_time) = 'Tuesday' THEN MAX(B.total_calls) ELSE NULL END AS 'Tuesday Calls',
        CASE WHEN WEEKDAY(B.poll_time) = 'Wednesday' THEN MAX(B.total_calls) ELSE NULL END AS 'Wednesday Calls',
        CASE WHEN WEEKDAY(B.poll_time) = 'Thursday' THEN MAX(B.total_calls) ELSE NULL END AS 'Thursday Calls',
        CASE WHEN WEEKDAY(B.poll_time) = 'Friday' THEN MAX(B.total_calls) ELSE NULL END AS 'Friday Calls'
FROM agent_poll AS B
WHERE B.poll_time > GETDATE() -7 --the last week
GROUP BY B.agent_id, DATENAME(WEEKDAY, B.poll_time) #Have to group by the datename as well as we're using it as part of the filter so it can't be aggregated
)
SELECT BB.agent_id, 
    MAX(BB.[Monday Calls]) AS 'Monday Calls', #now we are only grouping by the agent so we aggregate the bins 
    MAX(BB.[Tuesday Calls]) AS 'Tuesday Calls', 
    MAX(BB.[Wednesday Calls]) AS 'Wednesday Calls', 
    MAX(BB.[Thursday Calls]) AS 'Thursday Calls',
    MAX(BB.[Friday Calls]) AS 'Friday Calls'
FROM beepboop AS BB
GROUP BY BB.agent_id # only group by agent now

不幸的是，我没有成功地使它在MySQL中工作。因此，我假设它需要从许多子查询中构建，但是不能将它们放在正确的位置。这将返回agent_id以及当前星期的日期。

SELECT agent_id as "Agent",
STR_TO_DATE(CONCAT(yearweek(CURRENT_TIMESTAMP),' Monday'), '%X%V %W') as "Mon",
STR_TO_DATE(CONCAT(yearweek(CURRENT_TIMESTAMP),' Tuesday'), '%X%V %W') as "Tue",
STR_TO_DATE(CONCAT(yearweek(CURRENT_TIMESTAMP),' Wednesday'), '%X%V %W') as "Wed",
STR_TO_DATE(CONCAT(yearweek(CURRENT_TIMESTAMP),' Thursday'), '%X%V %W') as "Thu",
STR_TO_DATE(CONCAT(yearweek(CURRENT_TIMESTAMP),' Friday'), '%X%V %W') as "Fri"
from agent
order by Agent

Agent|Mon       |Tue       |Wed       |Thu       |Fri       |
-----|----------|----------|----------|----------|----------|
    1|2019-11-18|2019-11-19|2019-11-20|2019-11-21|2019-11-22|
    2|2019-11-18|2019-11-19|2019-11-20|2019-11-21|2019-11-22|
    3|2019-11-18|2019-11-19|2019-11-20|2019-11-21|2019-11-22|
    4|2019-11-18|2019-11-19|2019-11-20|2019-11-21|2019-11-22|
    5|2019-11-18|2019-11-19|2019-11-20|2019-11-21|2019-11-22|
    6|2019-11-18|2019-11-19|2019-11-20|2019-11-21|2019-11-22|
    7|2019-11-18|2019-11-19|2019-11-20|2019-11-21|2019-11-22|
    8|2019-11-18|2019-11-19|2019-11-20|2019-11-21|2019-11-22|
    9|2019-11-18|2019-11-19|2019-11-20|2019-11-21|2019-11-22|
   10|2019-11-18|2019-11-19|2019-11-20|2019-11-21|2019-11-22|

我相信我只需要延长每一天的时间范围，以使用它们提供的日期为条件。我应该从这里去哪里？

Answer 1

您可以使用相关子查询来筛选每个业务代表和工作日的最后一条记录，然后进行条件聚合：

select 
    agent_id agent,
    max(case when weekday(poll_time) = 0 then total_calls end) mon,
    max(case when weekday(poll_time) = 1 then total_calls end) tue,
    max(case when weekday(poll_time) = 2 then total_calls end) wed,
    max(case when weekday(poll_time) = 3 then total_calls end) thu,
    max(case when weekday(poll_time) = 4 then total_calls end) fri
from agent a
where poll_time = (
    select max(polltime)
    from agent a1
    where 
        a.agent_poll_id = a1.agent_poll_id 
        and weekday(a.poll_time) = weekday(a1.poll_time)
)
group by agent_id

您如何在MySQL中按日返回最大值？

1 个答案: