Question

我想检查以下内容

此设置有效

number = 100
divisor = 10

这些不是

number = 100
divisor = 0.1

方案1显示正确答案，但是方案2没有。显示正确结果的最佳方法是什么。

def isDivisible(number, divisor):
    return (number % divisor)

number = 100
divisor = 10

print("Scenario 1:")
print("")
print("Number = " + str(number))
print("Divisor = " + str(divisor))
print("")
print("Answer:")
if isDivisible(number, divisor) == 0:
    print("Answer: True")
    print("Value: " + str(isDivisible(number, divisor)))
else:
    print("Answer: False")
    print("Value: " + str(isDivisible(number, divisor)))

print("")
print("##################")
print("")

number = 100
divisor = 0.1

print("Scenario 2:")
print("")
print("Number = " + str(number))
print("Divisor = " + str(divisor))
print("")
print("Answer:")
if isDivisible(number, divisor) == 0:
    print("Answer: True")
    print("Value: " + str(isDivisible(number, divisor)))
else:
    print("Answer: False")
    print("Value: " + str(isDivisible(number, divisor)))

print("")

Answer 1

根据示例，您使用的是浮点数。浮点数有很多限制-最重要的是，它们的精度受到限制。坦率地说，即使可行，我也对浮点模量感到惊讶。它可能应该是TypeError。

尝试使用Python标准库中的decimal package，看看是否有更多的成功。

Answer 2

不确定这是否是正确答案，但似乎可以正常工作。我使用数字作为字符串转换为十进制。我尝试仅使用十进制而不转换为字符串，但是在“ number”变量的末尾有很多垃圾，因此无法解决。

from decimal import Decimal # Added this

def isDivisible(number, divisor):
    return (number % divisor)

number = 10
divisor = 0.0001
divisor = Decimal(str(divisor))
number = Decimal(str(number))

print("Number = " + str(number)) # Added this
print("Divisor = " + str(divisor)) # Added this
print("")
if isDivisible(number, divisor) == 0:
    print("Answer: True")
    print("Value: " + str(isDivisible(number, divisor)))
else:
    print("Answer: False")
    print("Value: " + str(isDivisible(number, divisor)))

print("")

检查数字是否可以在python中被另一个整数整除

2 个答案: