我们正在使用Laravel版本5. * 我们不想在我们的项目中更改此代码 response()-> json
它将反映整个应用程序,这很糟糕。因此,我们需要一个适当的解决方案,而我在此问题的评论中找到了解决方案。 谢谢。
这是场景:
$response = response()->json(['code' => 1,
'message' => 'Content-type is ABC',
'data' => ['code'=>1,'message'=>'Content-type is ABC']
]);
echo json_decode($response); // It always print null and nothing.
dd($response); // print Null
return $response; //You will get proper json response in function return.
答案 0 :(得分:2)
尝试使用
$response = response()->json(['code' => 1,
'message' => 'Content-type is ABC',
'data' => ['code'=>1,'message'=>'Content-type is ABC']
]);
$x = $response->getContent();
return $x;
OR
return $response;
输出将为
"{"code":1,"message":"Content-type is ABC","data":{"code":1,"message":"Content-type is ABC"}}"
答案 1 :(得分:1)
尝试getContent():
echo $response->getContent();
答案 2 :(得分:0)
$response = response()->json(['code' => 1,
'message' => 'Content-type is ABC',
'data' => ['code'=>1,'message'=>'Content-type is ABC']
]);
您可以直接打印
echo $response->getContent()