我正在使用Microsoft门户中的以下代码从Azure服务总线主题/订阅收发消息。代码运行正常。当我运行2个接收方代码实例时，总线在2个接收方之间分配消息。 10个发送&&接收5个。我只想知道如何在所有接收者中获取所有消息。
public class ServiceBusTopicSender
{
static final Gson GSON = new Gson();
public static void main(String[] args) throws Exception, ServiceBusException {
// TODO Auto-generated method stub
TopicClient sendClient;
String connectionString = "Endpoint=sb://basicbus.servicebus.windows.net/;"
+ "SharedAccessKeyName=RootManageSharedAccessKey;"
+ "SharedAccessKey=xxxxxpxxxxxxxxxxxxxxxxxx/xxxxxxxxxx=";
sendClient = new TopicClient(new ConnectionStringBuilder(connectionString, "basictopic"));
sendMessagesAsync(sendClient).thenRunAsync(() -> sendClient.closeAsync());
}
static CompletableFuture<Void> sendMessagesAsync(TopicClient sendClient) {
List<HashMap<String, String>> data =
GSON.fromJson(
"[" +
"{'name' = 'Einstein', 'firstName' = 'Albert'}," +
"{'name' = 'Heisenberg', 'firstName' = 'Werner'}," +
"{'name' = 'Curie', 'firstName' = 'Marie'}," +
"{'name' = 'Hawking', 'firstName' = 'Steven'}," +
"{'name' = 'Newton', 'firstName' = 'Isaac'}," +
"{'name' = 'Bohr', 'firstName' = 'Niels'}," +
"{'name' = 'Faraday', 'firstName' = 'Michael'}," +
"{'name' = 'Galilei', 'firstName' = 'Galileo'}," +
"{'name' = 'Kepler', 'firstName' = 'Johannes'}," +
"{'name' = 'Kopernikus', 'firstName' = 'Nikolaus'}" +
"]",
new TypeToken<List<HashMap<String, String>>>() {
}.getType());
List<CompletableFuture> tasks = new ArrayList<>();
for (int i = 0; i < data.size(); i++) {
final String messageId = Integer.toString(i);
Message message = new Message(GSON.toJson(data.get(i), Map.class).getBytes(UTF_8));
message.setContentType("application/json");
message.setLabel("Scientist");
message.setMessageId(messageId);
message.setTimeToLive(Duration.ofMinutes(2));
System.out.printf("Message sending: Id = %s\n", message.getMessageId());
tasks.add(
sendClient.sendAsync(message).thenRunAsync(() -> {
System.out.printf("\tMessage acknowledged: Id = %s\n", message.getMessageId());
}));
}
return CompletableFuture.allOf(tasks.toArray(new CompletableFuture<?>[tasks.size()]));
}
}
public class ServiceBusTopicReceiver
{
static final Gson GSON = new Gson();
public static void main(String[] args) throws Exception, ServiceBusException {
String connectionString = "Endpoint=sb://basicbus.servicebus.windows.net/;"
+ "SharedAccessKeyName=RootManageSharedAccessKey;"
+ "SharedAccessKey=xxxxxpxxxxxxxxxxxxxxxxxx/xxxxxxxxxx=";
SubscriptionClient subscription1Client = new SubscriptionClient(new ConnectionStringBuilder(connectionString,
"basictopic/subscriptions/basicsubscription"), ReceiveMode.PEEKLOCK);
registerMessageHandlerOnClient(subscription1Client);
}
static void registerMessageHandlerOnClient(SubscriptionClient receiveClient) throws Exception {
// register the RegisterMessageHandler callback
IMessageHandler messageHandler = new IMessageHandler() {
// callback invoked when the message handler loop has obtained a message
public CompletableFuture<Void> onMessageAsync(IMessage message) {
// receives message is passed to callback
if (message.getLabel() != null &&
message.getContentType() != null &&
message.getLabel().contentEquals("Scientist") &&
message.getContentType().contentEquals("application/json")) {
byte[] body = message.getBody();
Map scientist = GSON.fromJson(new String(body, UTF_8), Map.class);
System.out.printf(
"\n\t\t\t\t%s Message received: \n\t\t\t\t\t\tMessageId = %s, \n\t\t\t\t\t\tSequenceNumber = %s, \n\t\t\t\t\t\tEnqueuedTimeUtc = %s," +
"\n\t\t\t\t\t\tExpiresAtUtc = %s, \n\t\t\t\t\t\tContentType = \"%s\", \n\t\t\t\t\t\tContent: [ firstName = %s, name = %s ]\n",
receiveClient.getEntityPath(),
message.getMessageId(),
message.getSequenceNumber(),
message.getEnqueuedTimeUtc(),
message.getExpiresAtUtc(),
message.getContentType(),
scientist != null ? scientist.get("firstName") : "",
scientist != null ? scientist.get("name") : "");
System.out.println("Partition Key is ::::: " + message.getPartitionKey());
}
return receiveClient.completeAsync(message.getLockToken());
}
public void notifyException(Throwable throwable, ExceptionPhase exceptionPhase) {
System.out.printf(exceptionPhase + "-" + throwable.getMessage());
}
};
receiveClient.registerMessageHandler(
messageHandler,
// callback invoked when the message handler has an exception to report
// 1 concurrent call, messages are auto-completed, auto-renew duration
new MessageHandlerOptions(1, false, Duration.ofMinutes(1)));
}
}
答案 0 :(得分：0)
Azure Service Bus是一家经纪人。收到消息时，您使用的是Competing Consumer模式。这意味着，如果您有一个预订，而您的流程的多个实例侦听同一预订，则它们将不会收到相同的消息。他们只会得到一个子集，而这是其他实例未收到的。那是故意的。如果要让多个处理器实例接收相同的消息，则需要为每个处理器实例创建一个订阅。这样，发送给该主题的每条消息都将复制到每个订阅中，并且每个订阅者（接收者）将获得自己的副本。