我正在尝试确定在我的React Native Web项目中设置路由的最佳方法。我正在使用expo,并按照本指南使用Next JS https://docs.expo.io/versions/latest/guides/using-nextjs/,因此我拥有这样的App.js:
import index from "./pages/index";
import alternate from "./pages/alternate";
import { createStackNavigator } from "react-navigation-stack";
import { createAppContainer } from "react-navigation";
const AppNavigator = createStackNavigator(
{
index,
alternate
},
{
initialRouteName: "index"
}
);
const AppContainer = createAppContainer(AppNavigator);
export default AppContainer;
我关心的是如何最好地处理路由。我目前有这样的index.js页面设置。
import * as React from 'react'
import { StyleSheet, Button, Text, View } from 'react-native'
export default function App ({navigation}) {
return (
<View style={styles.container}>
{/* Native route */}
<Button
title="Go to Details"
onPress={() => navigation.navigate("alternate")}
/>
{/* Web route */}
<Text style={styles.link} accessibilityRole="link" href={`/alternate`}>
A universal link
</Text>
</View>
);
}
如您所见,当前需要使用单独的代码来呈现本机与Web路由。我想知道什么是处理这种渲染的最佳方法。我研究过使用React Navigation for web,并且不会反对,但似乎我应该坚持使用下一台路由器。
预先感谢您对处理这样的条件渲染的任何建议。
答案 0 :(得分:1)
有import { Platform } from 'react-native'
:
{Platform.OS === 'web' ? (
<Text
style={styles.link}
accessibilityRole="link"
href={`/alternate`}
>
A universal link
</Text>
) : (
<Button
title="Go to Details"
onPress={() => navigation.navigate("alternate")}
/>
)}
答案 1 :(得分:1)
为此使用reactnavigation网站支持
https://reactnavigation.org/docs/en/web-support.html
import { createSwitchNavigator } from "@react-navigation/core";
import { createBrowserApp } from "@react-navigation/web";
const MyNavigator = createSwitchNavigator(routes);
const App = createBrowserApp(MyNavigator);
// now you can render "App" normally