Question

我有一个列表listOfNumbers = [3,2,1,4,5,6,7,8,9,22,25,16,17,28]，我想按升序对该列表进行排序，但首先是奇数，然后是偶数，如下所示：

[1, 5, 7, 9, 11, 15, 19, 29,'startOF->evens', 4, 8, 10, 14, 16, 28, 32, 66]

没有排序功能

我已经尝试过了，但是出现错误

data_list = [3,2,1,4,5,6,7,8,9,22,25,16,17,28]
new_list = []
while data_list:
    minimum = data_list[0]
    for x in data_list: 
        if x < minimum:
            minimum = x
    new_list.append(minimum)
    data_list.remove(minimum)
    print (new_list)
def Huhu(data_list):
  ev_li = ''
    od_li = ''
    for i in data_list: 
        if (i % 2 == 0): 
            ev_li.append(i) 
        else: 
            od_li.append(i)
    print(new_list,od_li "startOF->evens",ev_li)

感谢我所做的回复

data_list = [3,2,1,4,5,6,7,8,9,22,25,16,17,28]
new_list = []

while data_list:
    minimum = data_list[0]  # arbitrary number in list 
    for x in data_list: 
        if x < minimum:
            minimum = x
    new_list.append(minimum)
    data_list.remove(minimum)
odds = []
evens = []
for i in new_list:
    if i % 2 == 0:
        evens.append(i)
    else:
        odds.append(i)
print(odds,"startOF->evens", evens)

Answer 1

您可以将sorted与自定义key参数一起使用进行排序。

>>> sorted(listOfNumbers, key=lambda i: (i%2==0, i))
[1, 3, 5, 7, 9, 17, 25, 2, 4, 6, 8, 16, 22, 28]

在这种情况下，您可以先按奇/偶排序，然后按值本身排序。

Answer 2

如果您想知道代码为什么失败：

data_list = [3,2,1,4,5,6,7,8,9,22,25,16,17,28]
new_list = []
while data_list:
    minimum = data_list[0]
    for x in data_list: 
        if x < minimum:
            minimum = x
    new_list.append(minimum)
    data_list.remove(minimum)
    print (new_list)
def Huhu(data_list):
    ev_li = list()
    od_li = list()
    for i in data_list: 
        if (i % 2 == 0): 
            ev_li.append(i) 
        else: 
            od_li.append(i)
    print(new_list,od_li, "startOF->evens",ev_li)

您有三个错误：

首先：缩进问题：

def Huhu(data_list):
  ev_li = ''
    od_li = '' <- Here

第二个：这里缺少逗号：

print(new_list,od_li [here] "startOF->evens",ev_li)

第三：

ev_li和od_li必须为list

但是可以肯定@CoryKramer是更干净的：P

在python中以奇数和偶数升序对列表进行排序

2 个答案: