Question

我有一个逻辑应用程序，它将azure函数用作http触发器并获取返回字符串。当azure函数要接收Base64字符串，使用信息创建文件并上传到分配的存储帐户时，每次运行它时，我都会不断从Azure函数中获取状态代码500内部服务器错误。经过多次尝试和错误，我推断出问题发生在从Base64字符串创建文件以及创建Blob容器客户端的时候。

所以请帮助我。

更新：根据您的一些建议，我对应用程序的见解进行了几次，并两次出现此错误：

Azure.RequestFailedException

消息：执行函数：BlobAdd时发生异常指定的资源名称包含无效字符

状态：400（指定的资源名称包含无效字符。）

ErrorCode：InvalidResourceName

失败的方法：Azure.Storage.Blobs.BlobRestClient + Container.CreateAsync_CreateResponse。

public static async Task<IActionResult> Run(
         [HttpTrigger(AuthorizationLevel.Function, "get", "post", Route = null)] HttpRequest req,
         ILogger log)
     {
         log.LogInformation("C# HTTP trigger function processed a request.");

     string requestBody = await new StreamReader(req.Body).ReadToEndAsync();

     return await Base64(requestBody);
 }

public static  async Task<IActionResult> Base64(string Base64Body)
{
    string HoldDBase = "";
    string TestBlobData = "null";

    if (Base64Body.Length > 10)
    {
        HoldDBase = Base64Body;
    }
    else
    {
        TestBlobData = "The Base64Body did not Pass";

        return (ActionResult)new OkObjectResult
           (
               new
               {
                   TestBlobData
               }
               );
    }

        //Connection string of the Storage Account Azure
        string ConnectionString = "xxxxxxxxx";

        // Create a BlobServiceClient object which will be used to create a container client
        BlobServiceClient blobServiceClient = new BlobServiceClient(ConnectionString);

        //Create a unique name of the container
        string ContainerName = "Base64_Blob" + Guid.NewGuid().ToString();

        //create the container and return a container client Object
        BlobContainerClient ContainerClient =  await blobServiceClient.CreateBlobContainerAsync(ContainerName); //Problem Here

        //create a local file in the Storage
        string localPath = "D:/Reliance/OlaForm/uploadsO";
        string fileName = "quickstart" + Guid.NewGuid().ToString() + ".txt";
        string localFilePath = Path.Combine(localPath, fileName);

        //convert string to bytes
        byte[] BaseBytes = Convert.FromBase64String(HoldDBase);

         //create file in local data
         await File.WriteAllBytesAsync(localFilePath,BaseBytes); //Problem Here        

      //get reference to a blob
      BlobClient blobclient = ContainerClient.GetBlobClient(fileName);

      // Open the file and upload its data
      FileStream uploadFileStream = File.OpenRead(localFilePath);
      await blobclient.UploadAsync(uploadFileStream);
     // blobclient.Upload(uploadFileStream);
      uploadFileStream.Close();

      //blob id from blobclient and return it
      TestBlobData = blobclient.ToString();

    TestBlobData = HoldDBase;
    return (ActionResult)new OkObjectResult
    (
        new {
            TestBlobData
        }
        );
}

Answer 1

您正在尝试写入“ D”盘。由于Azure功能无法直接访问磁盘，因此在尝试写入不存在的磁盘时会出现500错误。

要从Azure函数写入文件，可以使用Azure存储SDK。

Azure功能状态代码500内部服务器错误

1 个答案: