Question

只给出了电子邮件地址，我试图从字符串中删除电子邮件，相应人员的姓名和以下逗号（如果存在），无论电子邮件出现在字符串中的哪个位置。

var str = 'Peter Johnson <aa156@ss.edu>, Bob Cooper-Junior <aa1233@ss.edu>, John Michaels <qq@zzz.edu>';

所以，如果我要删除'aa1233@ss.edu'，我最终会：

var str = 'Peter Johnson <aa156@ss.edu>, John Michaels <qq@zzz.edu>';

由于

Answer 1

为什么不使用'，'作为分隔符来拆分字符串并找到哪个索引包含'aa1233@ss.edu'并重建没有该索引的字符串？ See Working Example Here

var newString = '';
var oldString = 'Peter Johnson <aa156@ss.edu>, Bob Cooper-Junior <aa1233@ss.edu>, John Michaels <qq@zzz.edu>';
var arrEmails = oldString.split(",");

for (i=0;i<arrEmails.length;i++){
    if (arrEmails[i].indexOf('aa1233@ss.edu') == -1){
        if (newString.length > 0) newString += ',' + arrEmails[i];
        else newString = arrEmails[i];
    }
}

alert(newString);

Answer 2

试试这个：

   var toRemove = "aa1233@ss.edu";
   var str = 'Peter Johnson <aa156@ss.edu>, Bob Cooper-Junior <aa1233@ss.edu>, John Michaels <qq@zzz.edu>';
   var arr = str.split(",");
   for (var i=0; i<arr.length; i++) {
      if (arr[i].indexOf(toRemove) != -1) {
         str = str.replace(arr[i] + ",", "");
         break;
      }
   }

   // output it
   alert(str);

输出

Peter Johnson <aa156@ss.edu>, John Michaels <qq@zzz.edu>

Answer 3

试试这个：

[^,]+? <aa1233@ss.edu>,?

这将满足您的需求，根据您的确切需求进行定制。

See here for more information.

Answer 4

通常，不使用正则表达式是更清晰的解决方案：

var people = str.split(", ");

for (var i = 0, l = people.length; i < l; i++) {
    if (people[i].indexOf(email) != -1) {
        people.splice(i, 1);
        str = people.join(", ");
        break;
    }
}

javascript - 字符串替换

4 个答案:

输出