Question

我需要将行合并为一行以进行计算摘要（SQL Server 2014）。

我的SQL查询是：

import { withRouter } from "react-router";

class Component extends React.Component {
  viewProfile = function () {
     console.log("clicked");
     this.props.history.push('/main');
  }

  render(){
    return (
       <Button color='primary' onClick={e => this.viewProfile()}>View Profile</Button>        
    )
  }

}
export default withRouter(Component);

此查询的结果是：

SELECT 
    [c].[Iso],
    SUM([r].[Quantity]) AS [Quantity],
    SUM([r].[Amount]) AS [Amount]
FROM
    [CarReport].[dbo].[Refuelling] [r]
INNER JOIN 
    [CarReport].[dbo].[Currency] [c] ON [r].[CurrencyId] = [c].[CurrencyId]
WHERE 
    [r].[DataId] = 15
    AND [r].[IsDeleted] = 0
GROUP BY 
    [r].[CurrencyId], [c].[Iso]

我想得到这个结果：

CZK |   50.00 | 1350,00
EUR |   23.00 | 463,20

添加新货币（x）时，必须附加新货币的结果：

CZK/EUR |   50.00/23.00 |   1350,00/463,20

有人可以帮我解决这个话题吗？

非常感谢

Answer 1

如果您正在运行SQL Server 2017，则可以添加另一级别的聚合并使用string_agg()：

SELECT
    STRING_AGG([Iso], '/') WITHIN GROUP(ORDER BY [Iso]) AS [Iso],
    STRING_AGG([Quantity], '/') WITHIN GROUP(ORDER BY [Iso]) AS [Quantity],
    STRING_AGG([Amount], '/') WITHIN GROUP(ORDER BY [Iso]) AS [Amount]
FROM (
    SELECT 
        [c].[Iso],
        SUM([r].[Quantity]) AS [Quantity]
        SUM([r].[Amount]) AS [Amount]
    FROM
        [CarReport].[dbo].[Refuelling] [r]
    INNER JOIN 
        [CarReport].[dbo].[Currency] [c] ON [r].[CurrencyId] = [c].[CurrencyId]
    WHERE 
        [r].[DataId] = 15
        AND [r].[IsDeleted] = 0
    GROUP BY 
        [r].[CurrencyId], [c].[Iso]
) t

ORDER BY的{{1}}子句使您在不同列中的值保持一致的顺序，因此您可以确定哪个数量和金额属于哪个货币（如果重要）。

Answer 2

类似的事情也应该适用于早期版本的MSSQL。

;with subQuery as (
    -- paste your base query here
    -- extend it with one additional column:
    -- ,ROW_NUMBER() OVER (ORDER BY ISO) RowNum
) 
select
    (select stuff((select '/' + convert(nvarchar(max), Iso) from subQuery order by RowNum for xml path('')), 1, 1, '')),
    (select stuff((select '/' + convert(nvarchar(max), Quantity) from subQuery order by RowNum for xml path('')), 1, 1, '')),
    (select stuff((select '/' + convert(nvarchar(max), Amount) from subQuery order by RowNum for xml path('')), 1, 1, ''))

如何使用分隔符将行合并为一行

2 个答案: