Question

我创建了一个应用程序，该应用程序记录了两个文件（来自麦克风和便携式摄像机）。录音工作正常，但现在我需要压缩音频文件并将其发送到服务器。不幸的是，第二个创建的文件即使在检入文件管理器时位于文件夹中，也对应用程序不可见。我仍然收到“没有这样的文件或目录”错误。我尝试使用以下行：

sendBroadcast(new Intent(Intent.ACTION_MEDIA_SCANNER_SCAN_FILE, Uri.fromFile(file)));

但是没有帮助。

这是一个创建WAV文件的函数，在这里我尝试使用sendBroadcast：

private void copyWaveFile(int mic){

        FileInputStream in;
        FileOutputStream out;
        long totalAudioLen;
        long totalDataLen;
        long longSampleRate = RECORDER_SAMPLERATE;
        int channels = 2;
        long byteRate = RECORDER_BPP * RECORDER_SAMPLERATE * channels/8;

        byte[] data = new byte[bufferSize];

        try {
            String filepath = Environment.getExternalStorageDirectory().getAbsolutePath();
            File file = new File(getFilename(mic)); //getFilename returns filename for a given mic

            in = new FileInputStream(getTempFilename(mic));
            out = new FileOutputStream(file);

            totalAudioLen = in.getChannel().size();
            totalDataLen = totalAudioLen + 36;

            WriteWaveFileHeader(out, totalAudioLen, totalDataLen,
                    longSampleRate, channels, byteRate); //here I write header for a WAV file

            while(in.read(data) != -1) {
                out.write(data);
            }

            in.close();
            out.close();
            sendBroadcast(new Intent(Intent.ACTION_MEDIA_SCANNER_SCAN_FILE, Uri.fromFile(file)));
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

    }

这是压缩功能：

public void zip(ArrayList<String> _files, String zipFileName) {
        try {
            zipPath = Environment.getExternalStorageDirectory().getAbsolutePath() + "/" + AUDIO_RECORDER_FOLDER + "/" + zipFileName;
            BufferedInputStream origin = null;
            FileOutputStream dest = new FileOutputStream(zipPath);
            ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(
                    dest));
            int BUFFER = 1024;
            byte[] data = new byte[1024];

            for (int i = 0; i < _files.size(); i++) {
                Log.v("Compress", "Adding: " + _files.get(i));
                FileInputStream fi = new FileInputStream(_files.get(i));
                origin = new BufferedInputStream(fi, BUFFER);

                ZipEntry entry = new ZipEntry(_files.get(i).substring(_files.get(i).lastIndexOf("/") + 1));
                out.putNextEntry(entry);
                int count;

                while ((count = origin.read(data, 0, BUFFER)) != -1) {
                    out.write(data, 0, count);
                }
                origin.close();
            }

            out.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

但不起作用。错误在哪里？

Answer 1

我建议您传递ArrayList<File>而不是ArrayList<String>。 File比String具有更多的功能，包括方法.exists()，该方法可以告诉您在开始发送该路径之前，路径是否正确。并迷惑自己。

应用程序看不到创建的文件

1 个答案: