我仍然在VBA中掌握更复杂的公式。
我想创建一个可以计算某些项目的工作时间的系统。例如,假设我的上班时间是6 AM-330PM。我在11/14的7AM开始一个项目,在11/16的9AM结束它。
我将如何进行计算,以便返回的值将是我每天工作的小时数,而不是24小时的滚动计算? (如果可能,还跳过周末吗?)
谢谢!!这是我试图使用的代码。...
Public Function NetWorkHours(dteStart As Date, dteEnd As Date) As Integer
Dim StDate As Date
Dim StDateD As Date
Dim StDateT As Date
Dim EnDate As Date
Dim EnDateD As Date
Dim EnDateT As Date
Dim WorkDay1Start As Date
Dim WorkDay1end As Date
Dim WorkDay2Start As Date
Dim WorkDay2end As Date
Dim Result As Integer
Dim MinDay As Integer
StDate = CDate(dteStart)
EnDate = CDate(dteEnd)
WorkDay1Start = DateValue(StDate) + TimeValue("08:00:00")
WorkDay1end = DateValue(StDate) + TimeValue("17:00:00")
WorkDay2Start = DateValue(EnDate) + TimeValue("08:00:00")
WorkDay2end = DateValue(EnDate) + TimeValue("17:00:00")
If (StDate > WorkDay1end) Then
StDate = DateAdd("d", 1, WorkDay1Start)
End If
If (StDate < WorkDay1Start) Then
StDate = WorkDay1Start
End If
If (EnDate > WorkDay2end) Then
EnDate = DateAdd("d", 1, WorkDay2Start)
End If
If (EnDate < WorkDay2Start) Then
EnDate = WorkDay2Start
End If
StDateD = CDate(Format(StDate, "Short Date"))
EnDateD = CDate(Format(EnDate, "Short Date"))
If StDateD = EnDateD Then
Result = DateDiff("n", StDate, EnDate, vbUseSystemDayOfWeek)
Else
MinDay = (8 * 60) 'Number of minutes of a working day. Change this if you change the start and end times.
'Extract the time from the two timestamps
StDateT = Format(StDate, "Short Time")
EnDateT = Format(EnDate, "Short Time")
' “计算第一天和第二天的分钟数。如果开始时间是下午5点之后或结束时间是8am之前,不知道该怎么办 结果= DateDiff(“ n”,StDateT,TimeValue(“ 17:00:00”),vbUseSystemDayOfWeek) 结果=结果+ DateDiff(“ n”,TimeValue(“ 08:00:00”),EnDateT,vbUseSystemDayOfWeek) '检查这两天是否休息。 如果DateDiff(“ n”,StDateT,TimeValue(“ 17:00:00”),vbUseSystemDayOfWeek)>(5 * 60)然后 结果=结果-60 如果结束
If DateDiff("n", TimeValue("08:00:00"), EnDateT, vbUseSystemDayOfWeek) > (5 * 60) Then
Result = Result - 60
End If
'Add 1 day to start date. This is to start the loop to get all the days between both dates.
StDateD = DateAdd("d", 1, StDateD)
Do Until StDateD = EnDateD
'If the date is not a saterday or a sunday we add one day.
If (Weekday(StDateD) > 1) And (Weekday(StDateD) < 7) Then
Result = Result + MinDay
'Check for the holiday. If the date is a holiday, then we remove one day
If Not IsNull(DLookup("[HolDate]", "Holidays", "[HolDate] = #" & Int(StDateD) & "#")) Then
Result = Result - MinDay
End If
End If
StDateD = DateAdd("d", 1, StDateD)
Loop
End If
NetWorkHours = Result
结束功能
答案 0 :(得分:1)
您可以使用DateDiff
计算日期(和时间)之间的时差。以下内容将使您非常接近想要做的事情:
Dim datStart As Date
Dim datEnd As Date
Dim sngShiftStart As Single
Dim sngShiftEnd As Single
Dim sngShiftDuration As Single
Dim lngMinutesWorked As Long
Dim lngOfftime As Long
Dim sngHoursWorked As Single
' Calculate shift length
sngShiftStart = 6
sngShiftEnd = 15.5
sngShiftDuration = sngShiftEnd - sngShiftStart
' Set start and end times
datStart = CDate("11/07/19 7:00")
datEnd = CDate("11/09/19 8:30")
lngMinutesWorked = DateDiff("n", datStart, datEnd)
lngOfftime = ((24 - sngShiftDuration) * 60) * (DateDiff("d", datStart, datEnd))
sngHoursWorked = (lngMinutesWorked - lngOfftime) / 60
MsgBox sngHoursWorked
这不考虑周末,但您应该可以轻松添加。您可以使用Weekday function检查开始日期的工作日是否小于结束日期。在这种情况下,请从2 * sngShiftDuration
中减去sngHoursWorked
。如果您的项目持续一周以上,则可以查找并减去更多的周末:
' Remove weekends
Dim sngWeekendHours As Single
If Weekday(datStart) > Weekday(datEnd) Then
' Weekend included
sngWeekendHours = (2 * sngShiftDuration) * (DateDiff("w", datStart, datEnd) + 1)
End If
sngHoursWorked = ((lngMinutesWorked - lngOfftime) / 60) - sngWeekendHours