Question

如果我的数据框为2000，并且假设品牌具有142个唯一值，并且我想计算从1到142的每个唯一值的出现频率，则值应该动态变化。

brand=clothes_z.brand_name
brand.describe(include="all")
unique_brand=brand.unique()
brand.describe(include="all"),unique_brand

输出：

(count       2613
unique      142
 top       Mango
 freq         54
 Name: brand_name, dtype: object,
array(['Jack & Jones', 'TOM TAILOR DENIM', 'YOURTURN', 'Tommy Jeans',
        'Alessandro Zavetti', 'adidas Originals', 'Volcom', 'Pier One',
        'Superdry', 'G-Star', 'SIKSILK', 'Tommy Hilfiger', 'Karl Kani',
        'Alpha Industries', 'Farah', 'Nike Sportswear',
        'Calvin Klein Jeans', 'Champion', 'Hollister Co.', 'PULL&BEAR',
        'Nike Performance', 'Even&Odd', 'Stradivarius', 'Mango',
        'Champion Reverse Weave', 'Massimo Dutti', 'Selected Femme Petite',
        'NAF NAF', 'YAS', 'New Look', 'Missguided', 'Miss Selfridge',
        'Topshop', 'Miss Selfridge Petite', 'Guess', 'Esprit Collection',
        'Vero Moda', 'ONLY Petite', 'Selected Femme', 'ONLY', 'Dr.Denim',
        'Bershka', 'Vero Moda Petite', 'PULL & BEAR', 'New Look Petite',
        'JDY', 'Even & Odd', 'Vila', 'Lacoste', 'PS Paul Smith',
        'Redefined Rebel', 'Selected Homme', 'BOSS', 'Brave Soul', 'Mind',
        'Scotch & Soda', 'Only & Sons', 'The North Face',
        'Polo Ralph Lauren', 'Gym King', 'Selected Woman', 'Rich & Royal',
        'Rooms', 'Glamorous', 'Club L London', 'Zalando Essentials',
        'edc by Esprit', 'OYSHO', 'Oasis', 'Gina Tricot',
        'Glamorous Petite', 'Cortefiel', 'Missguided Petite',
        'Missguided Tall', 'River Island', 'INDICODE JEANS',
        'Kings Will Dream', 'Topman', 'Esprit', 'Diesel', 'Key Largo',
        'Mennace', 'Lee', "Levi's®", 'adidas Performance', 'jordan',
        'Jack & Jones PREMIUM', 'They', 'Springfield', 'Benetton', 'Fila',
        'Replay', 'Original Penguin', 'Kronstadt', 'Vans', 'Jordan',
        'Apart', 'New look', 'River island', 'Freequent', 'Mads Nørgaard',
        '4th & Reckless', 'Morgan', 'Honey punch', 'Anna Field Petite',
        'Noisy may', 'Pepe Jeans', 'Mavi', 'mint & berry', 'KIOMI', 'mbyM',
        'Escada Sport', 'Lost Ink', 'More & More', 'Coffee', 'GANT',
        'TWINTIP', 'MAMALICIOUS', 'Noisy May', 'Pieces', 'Rest',
        'Anna Field', 'Pinko', 'Forever New', 'ICHI', 'Seafolly', 'Object',
        'Freya', 'Wrangler', 'Cream', 'LTB', 'G-star', 'Dorothy Perkins',
        'Carhartt WIP', 'Betty & Co', 'GAP', 'ONLY Tall', 'Next', 'HUGO',
        'Violet by Mango', 'WEEKEND MaxMara', 'French Connection'],
       dtype=object))

由于它仅显示芒果“ 54”的频率，因为它是最高频率，所以我希望每个值频率都像Jack & Jones，TOM TAILOR DENIM和YOURTURN的频率一样，等等开启...，并且值应该动态更改。

Answer 1

您可以简单地做到

Array
(
    [0] => node: /opt/lampp/lib/libstdc++.so.6: version `GLIBCXX_3.4.10' not found (required by node)
    [1] => node: /opt/lampp/lib/libstdc++.so.6: version `CXXABI_1.3.3' not found (required by node)
    [2] => node: /opt/lampp/lib/libstdc++.so.6: version `GLIBCXX_3.4.9' not found (required by node)
    [3] => node: /opt/lampp/lib/libstdc++.so.6: version `GLIBCXX_3.4.11' not found (required by node)
)

这将列出唯一值，并为您提供该熊猫系列中每个元素的出现频率。

Answer 2

from collections import Counter


ll = [...your list of brands...]
c = Counter(ll)
# you can do whatever you want with your counted values
df = pd.DataFrame.from_dict(c, orient='index', columns=['counted'])

如何从熊猫数据框中检查每个唯一值的频率？

2 个答案: