我有下表:
Date Open High Low Close
1-Oct-19 225.070007 228.220001 224.199997 224.589996
2-Oct-19 223.059998 223.580002 217.929993 218.960007
3-Oct-19 218.429993 220.960007 215.130005 220.820007
4-Oct-19 225.639999 227.490005 223.889999 227.009995
7-Oct-19 226.270004 229.929993 225.839996 227.059998
8-Oct-19 225.820007 228.059998 224.330002 224.399994
9-Oct-19 227.029999 227.789993 225.639999 227.029999
10-Oct-19 227.929993 230.440002 227.300003 230.089996
11-Oct-19 232.949997 237.639999 232.309998 236.210007
14-Oct-19 234.899994 238.130005 234.669998 235.869995
15-Oct-19 236.389999 237.649994 234.880005 235.320007
16-Oct-19 233.369995 235.240005 233.199997 234.369995
17-Oct-19 235.089996 236.149994 233.520004 235.279999
18-Oct-19 234.589996 237.580002 234.289993 236.410004
21-Oct-19 237.520004 240.990005 237.320007 240.509995
22-Oct-19 241.160004 242.199997 239.619995 239.960007
23-Oct-19 242.100006 243.240005 241.220001 243.179993
24-Oct-19 244.509995 244.800003 241.809998 243.580002
25-Oct-19 243.160004 246.729996 242.880005 246.580002
28-Oct-19 247.419998 249.25 246.720001 249.050003
29-Oct-19 248.970001 249.75 242.570007 243.289993
30-Oct-19 244.759995 245.300003 241.210007 243.259995
31-Oct-19 247.240005 249.169998 237.259995 248.759995
对于给定的日期范围(例如03Oct19到10Oct19之间),我想获取HIGH列的MAXIMUM值及其对应的日期值,LOW列的MINIMUM值及其对应的日期。 在上面的示例中,预期结果应为
| MAX(High) | High-Date | MIN(Low) | Min-Date |
+-------------+-----------+------------+-----------+
| 230.44002 | 10-Oct-19 | 215.130005 | 03-Oct-19 |
我正在尝试以下查询:
SELECT max(high)
, Date
, min(low)
, Date
FROM tbl1
where date>='2019-10-03'
and date<='2019-10-10'
group by date
但是,上面的代码缺少一些内容,因为它只是返回了所有行。
任何想法都应该使用(联接?还是嵌套查询?)
谢谢
答案 0 :(得分:2)
尝试这样的事情:
select * from
(SELECT high as "Max(high)"
, Date_c as "High-Date"
FROM tbl1
where Date_c >= '2019-10-03'
and Date_c <= '2019-10-10'
And high = (select max(high) from tbl1)) a
cross join
(SELECT low as "MIN(Low)"
, Date_c as "Min-Date"
FROM tbl1
where Date_c >= '2019-10-03'
and Date_c<= '2019-10-10'
And low = (select min(low) from tbl1)) b
这是MySQL 5.7的一个小DEMO。
或者如果由于某些原因您有两行相同,而您只想要一个结果:
select a.high as "Max(high)"
, a.Date_c "High-Date"
, b.low as "MIN(Low)"
, b.Date_c as "Min-Date"
from
(SELECT max(high) as "high"
, max(Date_c) as "Date_c"
FROM tbl1
where high = (select max(high)
from tbl1
where Date_c between '2019-10-03' and '2019-10-10')) a
cross join
(SELECT min(low) as "low"
, max(Date_c) as "Date_c"
FROM tbl1
where low = (select min(low)
from tbl1
where Date_c between '2019-10-03' and '2019-10-10')) b
这里是DEMO。
这是根据@SalmanA(Cheers!)建议的代码:
select A.high as "Max(high)"
, A.Date_c "High-Date"
, B.low as "MIN(Low)"
, B.Date_c as "Min-Date"
from
(SELECT High, Date_c
FROM tbl1
where Date_c between '2019-10-03' and '2019-10-10'
ORDER BY High DESC LIMIT 1) A
CROSS JOIN
(SELECT Low, Date_c
FROM tbl1
where Date_c between '2019-10-03' and '2019-10-10'
ORDER BY Low LIMIT 1
) B;
还有DEMO。
答案 1 :(得分:1)
您可以尝试以下操作:
SELECT
T1.*,T2.*
FROM
(
SELECT DATE AS YOUR_MX_DATE,HIGH AS YOUR_HG_VALUE
FROM TBL1
WHERE HIGH IN (
SELECT MAX(HIGH) AS MX_VALUE FROM TBL1
WHERE Date >='2019-10-03'
AND Date <='2019-10-10'
)
)T1 CROSS JOIN
(
SELECT DATE AS YOUR_MN_DATE,HIGH AS YOUR_MN_VALUE
FROM TBL1
WHERE LOW IN (
SELECT MIN(LOW) AS MN_VALUE FROM TBL1
WHERE Date >='2019-10-03'
AND Date <='2019-10-10'
)
) T2
答案 2 :(得分:1)
您首先需要找到指定日期范围内的最大值和最小值,然后与主表结合以获取相应的日期。结果将具有一行(同一日期的最高值和最低值)或两行(两个日期的最高值和最低值)或更多行(多个日期的同一最高值或最低值)。使用条件聚合来完善结果:
SELECT MIN(CASE WHEN t.High = v.High THEN t.High END) AS High -- MIN/MAX does not matter here
, MIN(CASE WHEN t.High = v.High THEN t.Date END) AS HighDate -- MIN for first date, MAX for last date
, MIN(CASE WHEN t.Low = v.Low THEN t.Low END) AS Low -- MIN/MAX does not matter here
, MIN(CASE WHEN t.Low = v.Low THEN t.Date END) AS LowDate -- MIN for first date, MAX for last date
FROM (
SELECT MAX(High) AS High
, MIN(Low) AS Low
FROM t
WHERE Date BETWEEN '2019-10-03' AND '2019-10-10'
) AS v
JOIN t ON t.High = v.High OR t.Low = v.Low
WHERE Date BETWEEN '2019-10-03' AND '2019-10-10'
答案 3 :(得分:1)
您可以使用此查询来获得所需的结果。它会在兴趣期内找到MAX(high)
和MIN(low)
值,然后JOIN
将这些值返回原始表以找到相应的日期。请注意,我们在日期值上使用MIN()
以避免出现超过一天的高/低值的情况;这给出了最早发生的日期。如果您希望出现高/低值的最新日期,请将其更改为MAX()
。
SELECT hl.high,
MIN(t1.date) AS high_date,
hl.low,
MIN(t2.date) AS low_date
FROM (SELECT MAX(high) AS high, MIN(low) AS low
FROM tbl1
WHERE `Date` BETWEEN '2019-10-03' AND '2019-10-10') hl
JOIN tbl1 t1 ON t1.high = hl.high AND t1.date BETWEEN '2019-10-03' AND '2019-10-10'
JOIN tbl1 t2 ON t2.low = hl.low AND t2.date BETWEEN '2019-10-03' AND '2019-10-10'
GROUP BY hl.high, hl.low
输出:
high low high_date low_date
230.44 215.13 2019-10-10 2019-10-03