Question

所以我在c＃中创建了一个HTTP处理程序（.ashx.cs），并且不断收到System.StackOverflowException，它似乎并没有告诉我问题出在哪里。我了解到，通过某些Google搜索，它可以告诉我他们太多的递归调用，但是我无法确切知道我在哪里进行此操作。

这是我的处理程序页面；

public void ProcessRequest(HttpContext context)
        {
            int userID;
            userID = Convert.ToInt32(HttpContext.Current.Session["UserID"]);

            string streamHash;
            streamHash = HttpContext.Current.Session["Stream"].ToString();

            int streamID;
            streamID = GetStreamID(streamHash);

            List<StreamUserMenues> listMenu = new List<StreamUserMenues>();

            using (DBEntities contextDB = new DBEntities())
            {
                var userStreamMenuList = contextDB.StreamMembers.ToList();

                foreach (var listItem in userStreamMenuList)
                {
                    StreamUserMenues streamUserMenu = new StreamUserMenues();
                    streamUserMenu.Id = listItem.StreamMembersID;
                    streamUserMenu.streamId = listItem.FKStreamID;
                    streamUserMenu.UserId = listItem.FKUserID;
                    streamUserMenu.UserNameText = listItem.FKUserID.ToString();
                    //streamUserMenu.isApproved = (bool) listItem.isUserApproved;
                    //streamUserMenu.isUserGuest = (bool) listItem.isGuest;
                    //streamUserMenu.isOnline = (bool) listItem.isUserOnline;
                    listMenu.Add(streamUserMenu);
                }
            }

            List<StreamUserMenues> menuTree = GetMenuTree(listMenu, streamID);
            JavaScriptSerializer js = new JavaScriptSerializer();
            context.Response.Write(js.Serialize(menuTree));
        }

在处理程序页面上，这是我收到错误消息的地方；

private List<StreamUserMenues> GetMenuTree(List<StreamUserMenues> list, int streamID)
        {

            return list.Where(x => x.streamId == streamID).Select(x => new StreamUserMenues()
            {
                Id = x.Id,
                streamId = x.streamId,
                UserId = x.UserId,
                UserNameText = x.UserId.ToString(),
                //isApproved = x.isApproved,
                //isUserGuest = x.isUserGuest,
                //isOnline = x.isOnline,
                List = GetMenuTree(list, x.streamId)

            }).ToList();

这是我叫处理程序的地方；

<script type="text/javascript">
        $(document).ready(function () {

            $.ajax({
                url: 'StreamUserMenuHandler.ashx',
                method: 'get',
                dataType: 'json',
                success: function (data) {
                    buildMenu($('#menu'), data);
                    $('#menu').menu();
                },
                error: function (err) {
                    alert(err.statusText);
                }
            });

            function buildMenu(parent, items) {
                $.each(items, function () {
                    //var li = $("<li><a href=" + window.location.href + "?StreamHash=" + this.URL + ">" + this.MenuText + "</a></li>");
                    //var myLink = '<li><a href="' + window.location.href + "'";
                    //myLink += '?StreamHash=';
                    var li = $("<li>" + this.UserNameText + "</li>");


                    if (!this.Active) {
                        li.addClass('ui-state-disabled');
                    }

                    li.appendTo(parent);

                    if (this.List && this.List.length > 0) {
                        var ul = $("<ul></ul>");
                        ul.appendTo(li);
                        buildMenu(ul, this.List);
                    }
                });

            }


        });
    </script>

我得到的例外是；

System.StackOverflowException
  HResult=0x800703E9
  Message=Exception of type 'System.StackOverflowException' was thrown.

Answer 1

让我们说：

StreamMembers包含5行，这些行具有相同的streamId，id为1001。

然后：

List<StreamUserMenues> menuTree = GetMenuTree(listMenu, "1001");
list.Where(x => x.streamId == 1001)将获得5行。
List = GetMenuTree(list, "1001")将一次又一次地给这5行，无休止....

我相信您的StreamMember.FKStreamID是指向StreamMember.StreamMembersID的FK，因此您的逻辑应该是：

private List<StreamUserMenues> GetMenuTree(List<StreamUserMenues> list, int streamID)
{
    return list.Where(x => x.streamId == streamID).Select(x => new StreamUserMenues() 
    {
        .....
          List = GetMenuTree(list, x.Id) //be aware: it's x.Id, not x.streamId
    }
}

Answer 2

在使用递归函数时，必须始终确保有一个基本案例，但事实并非如此。

在我看来，您只是一次又一次地传递相同的列表和ID，这将导致您的程序抛出错误。

在ASP.NET C＃中获取StackOverFlow异常

2 个答案: