对于SWIFT 5.1
如何获取字符串数组以与整数数组合并?
stringArray:[“ Tom”,“ Dick”,“ Harry”]
intArray:[1,2,3]
我正在寻找的结果是一个格式为String:Int
的列表汤姆:1
迪克:2
哈里:3
答案 0 :(得分:2)
要实现此目的,您必须链接一些很棒的高阶函数,如下所示:
let name = ["Tom", "Dick", "Harry"]
let id = [ 1, 2, 3]
let dict = zip(name, id).map { [$0.0 : $0.1] }
.reduce([:]) { $0.merging($1) { (current, _) in current } }
print(dict)
答案 1 :(得分:0)
这可以通过以下方式完成:
var intOne: [Int] = [1, 2, 3, 4]
var stringArray: [String] = ["a","b","c","d"]
var dictionary: [Int: String] = [:]
for (index, element) in intOne.enumerated() {
dictionary[element] = stringArray[index]
}
print(dictionary)
Output: [2: "b", 3: "c", 1: "a", 4: "d"]
extension Dictionary {
public init(keys: [Key], values: [Value]) {
precondition(keys.count == values.count)
self.init()
for (index, key) in keys.enumerated() {
self[key] = values[index]
}
}
}