Question

我尝试使用python编写网络自动化代码，但始终收到错误警告：

selenium.common.exceptions.ElementNotInteractableException：消息：元素不可交互

代码如下：

def commentAndLike():
random.seed()
likeOrNext = random.randint(0, 3)

if likeOrNext == 0:
    if check_exists_by_xpath("/html/body/div[3]/div[2]/div/article/div[2]/section[1]/span[1]/button/span"):
        likeButton = browser.find_element_by_xpath("/html/body/div[3]/div[2]/div/article/div[2]/section[1]/span[1]/button/span")
        likeButton.click()

        time.sleep(randomNumber(6, 10))

        if check_exists_by_xpath("/html/body/div[3]/div[2]/div/article/div[2]/section[1]/span[2]/button/span"):
            random.seed()
            randomComment = random.randint(0, 3)

            textArea = browser.find_element_by_xpath("/html/body/div[3]/div[2]/div/article/div[2]/section[3]/div[1]/form/textarea")

            if randomComment == 0:
                textArea.send_keys(comments[0])
            elif randomComment == 1:
                textArea.send_keys(comments[1])
            elif randomComment == 2:
                textArea.send_keys(comments[2])
            elif randomComment == 3:
                textArea.send_keys(comments[3])

            time.sleep(randomNumber(15,30))

            postButton = browser.find_element_by_xpath("/html/body/div[3]/div[2]/div/article/div[2]/section[3]/div/form/button")
            postButton.click()

            time.sleep(randomNumber(20,25))

            nextButton2 = browser.find_element_by_xpath("/html/body/div[3]/div[1]/div/div/a[2]")
            nextButton2.click()

            time.sleep(randomNumber(15,20))

        else:
            nextButton4 = browser.find_element_by_xpath("/html/body/div[3]/div[1]/div/div/a[2]")
            nextButton4.click()

            time.sleep(randomNumber(20, 25))

    else:
        nextButton1 = browser.find_element_by_xpath("/html/body/div[3]/div[1]/div/div/a[2]")
        nextButton1.click()

        time.sleep(randomNumber(20, 25))

else:
    nextButton = browser.find_element_by_xpath("/html/body/div[3]/div[1]/div/div/a[2]")
    nextButton.click()

    time.sleep(randomNumber(20,25))

尝试将send_keys移至textArea元素时抛出错误。

我知道我仍然需要改进代码并缩短nextButton的时间，但是我想首先解决问题。谢谢您的帮助！

Answer 1

根据问题描述进行了修改，其中向textArea发送密钥会引发错误。

您可以尝试使用Javascript设置textarea的值：

browser.execute_script("arguments[0].value = 'myValue';", textArea)

如果这不起作用，您可以尝试单击textArea首先将其激活：

browser.execute_script("arguments[0].click();", textArea)

browser.execute_script("arguments[0].value = 'myValue';", textArea);

在您的情况下，您可以将'myValue'替换为' + comments[0] + '

Answer 2

抛出这种异常是指尽管DOM上存在一个元素，但它并未处于可以交互的状态。您可以尝试实现某种等待机制，最好是这样的显式等待机制：

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

textArea = WebDriverWait(driver, 10).until(
    EC.presence_of_element_located((By.XPATH, "/html/body/div[3]/div[2]/div/article/div[2]/section[3]/div[1]/form/textarea"))

Python Selenium：元素不可交互

2 个答案: