由于伦敦的夏时制,我无法获得平日和周末的正确计数。在下面的小提琴中,2019年10月26日考虑的时间有时是工作日,有时是周末。 我想得到以下小提琴的输出是 “ workingDays”:1 “ weekendDays”:2
有什么建议吗?
var startDate = new Date('2019-10-26');
var endDate = new Date('2019-10-28');
var workingDays = number_of_working_days(startDate, endDate);
var weekendDays = number_of_weekend_days(startDate, endDate);
console.log({
'workingDays': workingDays,
'weekendDays': weekendDays
})
function number_of_working_days(startDate, endDate) {
var workingDays = 0;
for (var i = startDate; i <= endDate; i = i + (60 * 60 * 24)) {
if (i.getDay() <= 5) {
workingDays = workingDays + 1;
}
}
return workingDays;
}
function number_of_weekend_days(startDate, endDate) {
var weekendDays = 0;
for (var i = startDate; i <= endDate; i = i + (60 * 60 * 24)) {
if (i.getDay() > 5) {
weekendDays = weekendDays + 1;
}
}
return weekendDays;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>