检查对象是否存在，如果不存在则手动引发错误

Question

我需要检查表中是否存在对象，如果没有引发错误，则将其自动保存到django cronjoblog表中。

这是部分执行我想要的代码，但是它不会引发错误，而是将其保存到cronjoblog表中：

from django.core.exceptions import ObjectDoesNotExist

some_object= Some_object.objects.filter(active=True)
try:
    some_object.get()
except ObjectDoesNotExist:
    print("Either the entry or blog doesn't exist.")

我需要类似的东西：

some_object= Some_object.objects.filter(active=True)
if not some_object:
    raise ObjectDoesNotExist("Either the entry or blog doesn't exist.")

Answer 1

您可以如下修改现有代码。

try:
    some_object.get()
except ObjectDoesNotExist as e:
    raise ObjectDoesNotExist("Either the entry or blog doesn't exist.") from e