CUDA返回值错误35是什么意思?

时间:2019-11-12 06:49:06

标签: c++ cuda gpu-programming

我的简单C ++ cuda代码的源代码

#include <iostream>
#include <cuda.h>

using namespace std;

__global__ void AddIntsCUDA(int *a, int *b, int *c)
{
    *c = *a + *b;
}

int main()
{
    int a, b, c;
    int *d_a, *d_b, *d_c;
    int size = sizeof(int);

    cudaMalloc((void **)&d_a, size);
    cudaMalloc((void **)&d_b, size);
    cudaMalloc((void **)&d_c, size);


    a = 10;
    b = 35;
    c = 0;

    cudaMemcpy(d_a, &a, size, cudaMemcpyHostToDevice);
    cudaMemcpy(d_b, &b, size, cudaMemcpyHostToDevice);

    AddIntsCUDA<<<1, 1>>>(d_a, d_b, d_c);

    cudaMemcpy(&c, d_c, size, cudaMemcpyDeviceToHost);

    cout << "The Answer is "<< c << endl;

    cudaFree(d_a);
    cudaFree(d_b);
    cudaFree(d_c);

    system("pause");

    return 0;
}

Console Output 输出显示c = 0,但我希望a和b输出之和(应该是45,因为a = 10,b = 35) 解释一下这段代码到底是怎么回事

1 个答案:

答案 0 :(得分:2)

尝试在内核启动之后和复制之前添加cudaError_t err = cudaDeviceSynchronize();。并打印err的值。

使用const char* cudaGetErrorString ( cudaError_t error )在运行时获取错误字符串,或者在这里查看:
https://docs.nvidia.com/cuda/cuda-runtime-api/group__CUDART__TYPES.html#group__CUDART__TYPES_1gf599e5b8b829ce7db0f5216928f6ecb6

在出现错误号35的注释之后,似乎您需要更新驱动程序。