Question

如何在不使用任何库的情况下在python中解析文本文件并读取包含git repos URL的行？

注意：该文本文件包含10个git存储库的URL。

文本文件格式：

repo_name https://www.github.com/path/to/repo
repo_name https://www.github.com/path/to/repo
repo_name https://www.github.com/path/to/repo

编辑：对其进行了排序。

def main():
    # reading txt file
    opFile = open("testrepo/textfile.txt", "r")
    lines = opFile.readlines()
    opFile.close()

    for line in lines:
        line = line.strip()
        parts = line.split()
        repo_name = parts[0]
        branch = parts[1]
        git_url = parts[2]
        print("Repository name: {} \n Branch name: {} \n Git clone url: {}".format(repo_name, branch, git_url))

if __name__ == "__main__":
    main()

输出：

Repository name: repo_name
Branch name: master 
Git clone url: https://gitlab.com/path/to/repo.git

Answer 1

您的文件只是两部分：

repo_name ==> [0]
https://www.github.com/path/to/repo ==> [1]

所以您将给出一个错误：

IndexError: list index out of range

克隆git存储库的Python方法

1 个答案: