Question

从同一程序中获取随机结果

我正在使用python请求库进行后期调用。我的程序有时可以按预期工作，但有时会出现错误“ UnboundLocalError：分配前引用了本地变量'response'”。

def test_fun():
    try:
        response = requests.get(f"{Base_URI}/Calls.json", auth=(AccSid, AccToken))
    except Exception as err:
        print(f'Other error occurred: {err}')

    assert response.status_code == 200

"UnboundLocalError: local variable 'response' referenced before assignment"

Answer 1

就像Green Cloak Guy所说的那样，当发生异常时，您的response变量是未定义的。这会导致错误。要解决此问题，您可以在else中添加try语句：

def test_fun():
    try:
        response = requests.get(f"{Base_URI}/Calls.json", auth=(AccSid, AccToken))
    except Exception as err:
        print(f'Other error occurred: {err}')
    else:
        assert response.status_code == 200

在没有引发异常的情况下运行else块。请注意，这不同于finally，后者始终运行无论是否引发错误。

Answer 2

如果请求失败，则可以使用raise_for_status()引发异常。

try:
    response = requests.get(url)

    # raise exception only if the request was unsuccessful
    response.raise_for_status()
except HTTPError as err:
    print(err)
else:
    # check the exact status and do your stuff.

UnboundLocalError：分配前引用了本地变量“响应”

2 个答案: