我的组件SkeletonComponent
中带有标签:
<div class="tabs">
<div class="tab" *ngIf="showTab(1)"><app-journal></app-journal></div>
<div class="tab" *ngIf="showTab(2)"><app-journal-extended></app-journal-extended></div>
</div>
因此,有一种机制可以按条件激活选项卡。它放置在父组件SkeletonComponent
中。
现在,我想添加路由,以按路由激活特定的标签:
{ path: "skeleton", component: SkeletonComponent, children: [
{
path: "journal",
component: JournalComponent
},
{
path: "journal/:id",
component: JournalExtendedComponent
}
]},
这是正确的方法吗?
答案 0 :(得分:2)
如果要让路由器处理此问题,请不要使用模板中的组件。使用路由器插座。本示例使用了“材料组件”中的“选项卡”。请更改为您的用户界面详细信息。您还需要将JournalExtendedComponent的子路由路径更改为journal/details/:id
skeleton.component.html
<nav mat-tab-nav-bar>
<button mat-tab-link *ngFor="let item of menuItems" (click)="selectTab(item)" [active]="activeTabIndex == item.id">{{item.title}}</button>
</nav>
<router-outlet></router-outlet>
skeleton.component.ts
export class JobsForTutorComponent {
menuItems: MenuItem[] = [
{
id: 0,
title: 'Tab Title 1',
route: '/route-to-component',
},
{
id: 1,
title: 'Tab Title 2',
route: '/route-to-other-component'
}
];
activeTabIndex: number;
constructor(
private router: Router,
private route: ActivatedRoute) {
const routedMenuItem = this.menuItems.find(menuItem => menuItem.route === this.router.url);
if (routedMenuItem) {
this.selectTab(routedMenuItem);
} else {
this.activeTabIndex = 0;
}
}
selectTab(tabItem: MenuItem) {
this.activeTabIndex = tabItem.id;
this.router.navigate([tabItem.route]);
}
}
menu-item.model.ts
export interface MenuItem {
id?: number;
title?: string;
route?: string;
}
编辑:根据情况进行路由
{
path: "journal",
component: SkeletonComponent,
children: [
{
path: "overview",
component: JournalComponent
},
{
path: "detail/:id",
component: JournalExtendedComponent
}
]
}
组件中的menuItems数组将为:
menuItems: MenuItem[] = [
{
id: 0,
title: 'Overview',
route: '/overview',
},
{
id: 1,
title: 'Details',
route: '/detail'
}
];