当时,在“选择”框中选择一个选项时,其余选项变为多个值。如何防止重复的值?
import Select from 'react-select';
const dataOptions = [];
class App extends React.Component {
constructor(props) {
super(props);
this.data = [];
this.getData();
}
getData = () => { api.request({url: `/getdata`}).then(res => res.map(el => this.data[el.id] = el.name)) }
addData = () => {
const { selectedId } = this.state;
var datas = this.data;
console.log(datas);
datas.map((name, index) => {
if (!dataOptions.includes(name)) {
console.log('b4 push:', dataOptions)
dataOptions.push({ value: index, label: name });
console.log('aftr push:', dataOptions)
}
});
return (
<Select options={dataOptions}
isMulti
/>
);
}
}
此语法中发生了错误:
datas.map((name, index) => {
if (!dataOptions.includes(name)) {
dataOptions.push({ value: index, label: name });
}
});
控制台结果
[ "data-1", "data-2", "data-3"]
b4 push: [
{value: 1, label: "data-1"}
{value: 2, label: "data-2"}
{value: 3, label: "data-3"}
]
aftr push: [
{value: 1, label: "data-1"}
{value: 2, label: "data-2"}
{value: 3, label: "data-3"}
]
P.S:这里在aftr push中,我已经从下拉菜单中选择了第一个选项;因此,结果如果不应显示在数组值中。
预先感谢...!
答案 0 :(得分:2)
destructuring
语法应类似于
datas.map(({name, index}) => {
if (!dataOptions.includes(name)) {
dataOptions.push({ value: index, label: name });
}
});
此外,您不需要外部数组即可将数据推送到map函数中,因为该函数默认情况下会返回一个数组,您可以像下面这样简单地完成
let expected_data=datas.map(({name, index}) => {
if (!dataOptions.includes(name)) {
return { value: index, label: name };// return a value
}
});
expected_data
将包含操作后所需的数据
查看摘要-
let data = [{
"name": 1,
"index": 2
}, {
"name": 11,
"index": 21
}]
console.log(data.map(({
index,
name
}) => {
return {
value: index,
label: name
}
}))
您最好使用Array.some()
来查找
datas.map((name,index) => { // here index is the iterator
if(!dataOptions.some(({value,label})=>label==name ))
{
dataOptions.push({ value: index, label: name });
}
});