Question

在将数据插入数据库后尝试刷新此数据表时遇到了一些麻烦。我希望数据表在javascript ajax上刷新，但是我不希望整个页面刷新。

我是数据表的新手，似乎无法弄清楚该怎么做。

任何帮助将不胜感激。

JavaScript

        $.ajax({
            url: 'post_project_definition',
            type: 'GET',
            data: {
                discID: $("#disciplinesProjDef").val(),
                discComment: $("#txtDiscipComment").val(),
            },
            success: () => {
                swal({
                    type: 'success',
                    title: 'Your comment has been added successfully'
                });
            }
        })
        $.getJSON('selectProjectDefinitionDescription', function (data) {
            $.each(data, function (i, item) {
                ProjDefTable.push([data[i].id,data[i].definition_name, data[i].description, 
                    "<input type='button' class='btn btn-danger' id='" + data[i].id + "delete' value='-'></input>"+
                    "<script>"+
                    "   $('#"+data[i].id+"delete').on('click', () => {" +
                    "       $.ajax({"+
                    "           url: 'delete_project_definition',"+
                    "           type: 'GET',"+
                    "           data: { "+
                    "               project_def_id: '"+data[i].id+"' "+
                    "           },"+
                    "       });"+
                    "   });" +
                    "</script>"
                ]);

                var table = $("#projDiscComTable").DataTable();
                table.clear().draw();
                table = $("#projDiscComTable").DataTable({
                    data: ProjDefTable,
                    columns: [
                        {title: "ID"},
                        { title: "Discipline Name" },
                        { title: "Discipline Description" },
                        { title: "Delete" },
                    ],
                    destroy: true
                });
            })//end else
        });
    });

PHP

public function selectProjectDefinitionDescription()
{
    $session_data = $this->session->userdata('logged_in');
    $id = $session_data['id'];
    $type =  $session_data['usertype'];
    $project_id = $session_data['project_id'];

    $stuff = $this->Projects_Model->load_Project_Definition_Discipline($project_id);
    echo $stuff;
}

HTML

<table id="projDiscComTable" class="table table-hover display">
  <thead>
   <tr>
    <th>ID</th>
    <th>Disciple</th>
    <th>Discipline Comment</th>
    <th>Delete</th>
   </tr>
  </thead>
</table>

Answer 1

我并没有使用DataTable，但是我相信使用它们是为了轻松地为您的HTML表提供各种功能，例如排序等。（Reference）

来到这里，我相信您的范围是基于AJAX响应刷新表的内容，而不必刷新整个页面。

您可以使用jQuery的append()和remove()函数来做到这一点。一个简单的算法就是这样：

首先，您可以在页面中某处隐藏一行HTML示例，如下所示：

<div id="definition-row-sample">
    <tr class="definition-row">
        <td class="definition-id"></td>
        <td class="definition-name"></td>
        <td class="definition-description"></td>
        <td class="definition-delete"></td>
    </tr>
</div>

将.definition-row隐藏起来，使其不会显示在页面中。
现在，当您通过AJAX提取数据时，请先使用$('.definition-row').remove()删除所有行，然后遍历数据并将其附加到表中的每一行：

    $.each(data, function (i, item) {
        $('#definition-row-sample').find('.definition-id').text(data[i].id);
        $('#definition-row-sample').find('.definition-name').text(data[i].definition_name);
        $('#definition-row-sample').find('.definition-description').text(data[i].description);
        //then simply append it to the table
        let content = $('#definition-row-sample').find('.definition-row').clone();
        $('#projDiscComTable').append(content);
    });

对于删除，您可以定义一个普通的函数，例如：

function definition_delete(id) {
    $.ajax({
        url: 'delete_project_definition',
        type: 'GET',
        data: {
           project_def_id:id
        }
    });   
}

document.on('click', '.definition-delete', function(){
    let id = $(this).parent().find('.definition-id').text();
    definition_delete(id);
});

我还没有测试代码，但是我确信您能理解并实现它，因为我也使用了与我的项目之一相似的逻辑。

Answer 2

插入注释后，仅刷新表怎么样？？

$('#projDiscComTable').DataTable().ajax.reload();

$.ajax({
            url: 'post_project_definition',
            type: 'GET',
            data: {
                discID: $("#disciplinesProjDef").val(),
                discComment: $("#txtDiscipComment").val(),
            },
            success: () => {
                $('#projDiscComTable').DataTable().ajax.reload();
                swal({
                    type: 'success',
                    title: 'Your comment has been added successfully'
                });
            }
        })

不确定这是否符合您的要求，但是您仍然可以在插入评论后刷新它。

Answer 3

我发现了这一点，我成功地在ajax中重新绘制了表格，从我所看到的来看，它似乎可以正常工作。但是，谢谢您的所有回答。以后我会用你们的建议。

var ProjDefTable = [];
$('#btnDiscipCommPost').on('click', () => {
    $.ajax({
        url: 'post_project_definition',
        type: 'GET',
        data: {
            discID: $("#disciplinesProjDef").val(),
            discComment: $("#txtDiscipComment").val(),
        },
        success: () => {
            swal({
                type: 'success',
                title: 'Your comment has been added successfully'
            });
            $.getJSON('selectProjectDefinitionDescription', function (data) {
                $.each(data, (i) => {
                    ProjDefTable.push([data[i].id,data[i].definition_name, data[i].description, 
                    "<input type='button' class='btn btn-danger' id='" + data[i].id + "delete' value='-'></input> <span id='" + data[i].id + "deleted' style='display: none; font-weight: 700;'>DELETED</span>"+
                    "<script>"+
                    "   $('#"+data[i].id+"delete').on('click', () => {" +
                    "       $.ajax({"+
                    "           url: 'delete_project_definition',"+
                    "           type: 'GET',"+
                    "           data: { "+
                    "               project_def_id: '"+data[i].id+"' "+
                    "           },"+
                    "           success: () => {"+
                    "               var x = document.getElementById('" + data[i].id + "delete');" +
                    "               x.style.display = 'none';" +
                    "               var y = document.getElementById('" + data[i].id + "deleted');" +
                    "               y.style.display = 'block';" +
                    "           } "+
                    "       });"+
                    "   });" +
                    "</script>"
                    ]);

                    var table = $("#projDiscComTable").DataTable();
                    table.clear().draw();
                    table = $("#projDiscComTable").DataTable({
                        data: ProjDefTable,
                        columns: [
                            {title: "ID"},
                            { title: "Discipline Name" },
                            { title: "Discipline Description" },
                            { title: "Delete" },
                        ],
                        destroy: true
                    });
                })//end else
            });
            var ProjDefTable = [];
        }
    })
});

单击按钮后仅刷新DataTable

3 个答案: