Question

我需要从一张桌子上的不同查询中获得多个结果。例如，我需要获取一张表的计数，总和，平均值。我应该这样做还是有更短的方法？

  public function index()
    {
        $count = Patient::all()->count();
        $dateCount = Patient::where('date', date("Y-m-d"))->count();
        $loanAmount = DB::table('patients')->sum('loan_amount');
        $payAmount = DB::table('patients')->sum('pay_amount');
        return view('index', compact('count','dateCount','loanAmount' ,'payAmount'));
    }

如果您看到所有查询都针对一个表以获取特定结果，那么基本上没有一种方法可以通过单个查询来获得这些结果吗？

Answer 1

您可以执行以下操作。

public function index()
    {
        $patient = Patient::all();
        $count = $patient->count();
        $dateCount = Patient::today()->count();
        $loanAmount =  $patient->sum('loan_amount');
        $payAmount =  $patient->sum('pay_amount');
        return view('index', compact('count','dateCount','loanAmount' ,'payAmount'));
    }

您还可以在患者模型中创建范围：

public function scopeToday($query) {
  return $query->where('date', date("Y-m-d"));
}

Answer 2

您可以通过数据库查询执行以下操作：

  $data=\DB::table('patients')
  ->selectRaw('count(id) as count,sum(loan_amount) as loanAmount,sum(pay_amount) as payAmount,sum(case when date = "'.date("Y-m-d").'" then 1 else 0 end) AS dateCount')
  ->first();

您也可以使用雄辩的方法执行此操作，但是它将返回您的收藏集。

  $data=Patient::selectRaw('count(id) as count,sum(loan_amount) as loanAmount,sum(pay_amount) as payAmount,sum(case when date = "'.date("Y-m-d").'" then 1 else 0 end) AS dateCount')
  ->first();

在laravel中处理多个查询的任何简便方法？

2 个答案: