我知道有一种方法可以使程序不四舍五入,但是我无法弄清楚,每次尝试时,它都会向我抛出不同的错误。所以我的代码减去所有舍入后的尝试都是
public class TheoryTest {
public static void main (String[] args) {
System.out.printf("%-15s%-15s%5s%-15s%-15s\n", "Feet", "Meter", "| ", "Meter", "Feet");
System.out.println("----------------------------------------------------------");
double foot = 1.0; double meter = 20.0;
for (int i = 1; i <= 10; foot++, meter += 5, i++) {
System.out.printf("%-15.1f%-15.3f%5s%-15.1f%-15.3f\n", foot, footToMeter(foot), "| ", meter,
meterToFoot(meter));
}
}
public static double footToMeter(double foot) {
Math.floor(return 0.305*foot);
}
public static double meterToFoot(double meter) {
Math.floor(return);
return 3.2787*meter;
}
}
错误:表达的非法开始 Math.floor(return 0.305 * foot);
错误:“;”预期 Math.floor(return 0.305 * foot);
错误:表达的非法开始 Math.floor(return 0.305 * foot);
错误:“;”预期 Math.floor(return 0.305 * foot);
错误:表达的非法开始 Math.floor(return);
错误:“;”预期 Math.floor(return);
6个错误 C:\ Users \ Shannon Reynolds \ Desktop \ try \ LabChapter69 \ nbproject \ build-impl.xml:930:执行此行时发生以下错误:
C:\ Users \ Shannon Reynolds \ Desktop \ try \ LabChapter69 \ nbproject \ build-impl.xml:270:编译失败;有关详细信息,请参见编译器错误输出。 失败(总时间:1秒)
答案 0 :(得分:0)
该语句已关闭...返回double的函数应返回一个值,而不是参数列表中的返回。
更改:
public static double footToMeter(double foot) {
Math.floor(return 0.305*foot);
}
public static double meterToFoot(double meter) {
Math.floor(return);
return 3.2787*meter;
}
...至:
public static double footToMeter(double foot) {
return Math.floor(0.305*foot);
}
public static double meterToFoot(double meter) {
return 3.2787*meter;
}