在输入验证时反应初始状态

Question

我花了一个多小时努力解决如何在验证输入中设置初始状态。

这是我的代码示例：

const {useReducer, useEffect, useState} = React;

const BasicInput = props => {
	const [isValidated, setIsValidated] = useState(true)

	useEffect(() => {
			setIsValidated(props.validation)
      console.log(props.validation)
	},[props.validation])
	
	return (
		<div className='input-box'>			
			<input
        className={`${!isValidated && 'not-valid'}`}
				type='text'
				name={props.name}
				required
				onChange={props.handleInput}
			/>
		</div>
	)
}

function contactFormReducer(state, action) {
	switch (action.type) {
		case 'email':
			return {...state, name: {
				value: action.payload,
				isValidate: /^.+(@).*\.[a-z]{2}$/.test(action.payload)
			}}
	}
}

const ExampleForm = () => {
	const [formData, dispatch] = useReducer(contactFormReducer, {
		name: {
			value: null,
			isValidate: false
		}
	})

	return (	
					<BasicInput						
						name='email'
						label='label'
						handleInput={e => dispatch({type: 'email', payload: e.target.value})}
						validation={formData['name'].isValidate}
					/>
	)
}

ReactDOM.render(
  <ExampleForm title="Example using simple hook:" />,
  document.getElementById("root")
);

.not-valid {
	border: 2px solid red;
	color: red!important;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.8.4/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.8.4/umd/react-dom.production.min.js"></script>
<div id='root'>
</div>

如您所见，初始输入状态设置为无效，这没关系，但是对于第一次显示的表单来说，它看起来很糟糕。我想知道如何不设置样式not-valid，同时在第一次渲染时将验证保持为false。我需要对此有一些新的见解，非常感谢任何帮助和建议。

更新

发布此帖子后，我发现了非常满意的解决方案，但仍然对性能不满意：

const {useReducer, useEffect, useState} = React;

const BasicInput = props => {
	const [isValidated, setIsValidated] = useState(true)
  const [isFocus, setIsFocus] = useState(false)
  
  useEffect(() => {
		if (isFocus) {
			setIsValidated(props.validation)
      console.log(props.validation)
		}
	})

	const handleFocus = () => {		
		setIsFocus(true)
	}
	
	return (
		<div className='input-box'>			
			<input
        className={`${!isValidated && 'not-valid'}`}
				type='text'
				name={props.name}
				required
				onChange={props.handleInput}
        onFocus={handleFocus}
			/>
		</div>
	)
}

function contactFormReducer(state, action) {
	switch (action.type) {
		case 'email':
			return {...state, name: {
				value: action.payload,
				isValidate: /^.+(@).*\.[a-z]{2}$/.test(action.payload)
			}}
	}
}

const ExampleForm = () => {
	const [formData, dispatch] = useReducer(contactFormReducer, {
		name: {
			value: null,
			isValidate: false
		}
	})

	return (	
					<BasicInput						
						name='email'
						label='label'
						handleInput={e => dispatch({type: 'email', payload: e.target.value})}
						validation={formData['name'].isValidate}
					/>
	)
}

ReactDOM.render(
  <ExampleForm title="Example using simple hook:" />,
  document.getElementById("root")
);

.not-valid {
	border: 2px solid red;
	color: red!important;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.8.4/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.8.4/umd/react-dom.production.min.js"></script>
<div id='root'>
</div>

每次触发onChange事件时，此解决方案将重新呈现我的输入组件。知道如何预防吗？