我想创建一个函数,该函数合并具有不同列号的数据帧列表,并且行具有我想保留的不同名称。本质上,我想堆叠其中列名仅成为要附加的另一行的数据框。
df <- list()
df[[1]] <- data.frame(d = c(4,5), e = c("c", "d"))
rownames(df[[1]]) <- c("df2_row_1", "df2_row_2")
df[[2]] <- data.frame(a = c(1,2,3), b = c("a", "b", "c"), c = c("one", "two", "three"))
rownames(df[[2]]) <- c("df1_row_1", "df1_row_2", "df1_row_3")
df[[3]] <- data.frame(f = c(6,7,8), g = c("e", "f", "g"), h = c("one", "two", "three"), w = c(100,101,102))
rownames(df[[3]]) <- c("df3_row_1", "df3_row_2", "df3_row_3")
do.call(bind_rows, df)
d e a b c f g h w
1 4 c NA <NA> <NA> NA <NA> <NA> NA
2 5 d NA <NA> <NA> NA <NA> <NA> NA
3 NA <NA> 1 a one NA <NA> <NA> NA
4 NA <NA> 2 b two NA <NA> <NA> NA
5 NA <NA> 3 c three NA <NA> <NA> NA
6 NA <NA> NA <NA> <NA> 6 e one 100
7 NA <NA> NA <NA> <NA> 7 f two 101
8 NA <NA> NA <NA> <NA> 8 g three 102
d e
df2_row_1 4 c
df2_row_2 5 d
a b c
df1_row_1 1 a one
df1_row_2 2 b two
df1_row_3 3 c three
f g h w
df3_row_1 6 e one 100
df3_row_2 7 f two 101
df3_row_3 8 g three 102
我尝试过(未成功)创建一个函数,该函数查找最长的数据帧,然后将空列添加到比最长的数据帧短的数据帧中,然后为所有数据帧赋予相同的名称。
我也意识到这不是更加整洁-这可能吗?
谢谢!
答案 0 :(得分:1)
这可以通过for循环来实现(我认为可以通过mapply
至,检查?mapply
来实现)。总体策略是用NA填充列表中的每个df(cbind
填充它们),然后rbindlist
填充结果列表:
library(data.table)
cols <- max(sapply(df, ncol))
# This is the length of the NA vectors that make the cbinding dfs:
lengths <- (cols - sapply(df, ncol))*sapply(df, nrow)
newdf <- list()
for (i in 1:length(df)){
if (ncol(df[[i]]) != cols){
newdf[[i]] <- cbind(df[[i]],
as.data.frame(matrix(rep(NA, lengths[i]),
ncol = lengths[i] / nrow(df[[i]]))))
} else {
newdf[[i]] <- df[[i]]
}
}
rbindlist(newdf, use.names = FALSE)
这将导致:
d e V1 V2
1: 4 c <NA> NA
2: 5 d <NA> NA
3: 1 a one NA
4: 2 b two NA
5: 3 c three NA
6: 6 e one 100
7: 7 f two 101
8: 8 g three 102