Question

给出python中的字典列表

my_list=[{'id':0,'name':'cube0_cluster0','member_ids': [429, 432, 435]}, 
{'id': 1,'name': 'cube0_cluster1','member_ids': [0, 4, 5]}, 
{'id':0,'name':'cube1_cluster1','member_ids': [4, 706, 800]}]

我要为member_ids打印所有cube{ }_cluster1

我的预期输出是打印[0,4,5,706,800]

任何帮助将不胜感激

我尝试过

for k in my_list: for j in range(len(my_list)): if k['name']=='cube{}_cluster1'.format(j): print(k['member_ids'])

但是我得到两个单独的输出，分别为[0,4,5]和[4,706,800]

Answer 1

尝试这个。

import re    
member_ids = []
for di in my_list:
    if re.match('cube\d_cluster1', di['name']):
        member_ids += di['member_ids']
print(member_ids)

Answer 2

您还可以使用列表推导。

my_list=[{'id':0,'name':'cube0_cluster0','member_ids': [429, 432, 435]}, 
{'id': 1,'name': 'cube0_cluster1','member_ids': [0, 4, 5]}, 
{'id':0,'name':'cube1_cluster1','member_ids': [4, 706, 800]}]


res = [j for i in my_list for j in i['member_ids'] if "cluster1" in i["name"]]

print (res) # return list
print (set(res)) # to return distinct data

# Result
# [0, 4, 5, 4, 706, 800]
# {0, 800, 706, 4, 5}

我希望这对您有所帮助！

在python中遍历字典列表

2 个答案: